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vovangra [49]
3 years ago
12

What is a free body diagram? what is it used for?

Chemistry
1 answer:
shepuryov [24]3 years ago
3 0

Answer:

A free body diagram is used to calculate static and dynamic forces acting on an object. In other words, a free body diagram is the starting point to develop a mathematical model to find and calculate various forces acting on a body.

Explanation:

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HELP ME PLEASE ASAP. I'LL MARK YOU BRAINLIEST <br> ITS NUMBER 23.
Ivanshal [37]

Answer:

The answer is A

Explanation:

5 0
3 years ago
Compare the modern (electron cloud) model of the atom with Bohr’s atomic model. Which of these statements describe the two model
AfilCa [17]

Answer:

B. Bohr’s model electrons cannot exist between orbits, but in the electron cloud model, the location of the electrons cannot be predicted.

AND

C. The modern model explains all available data about atoms; Bohr’s model does not.

Explanation:

The answers are right on Edge. :)

6 0
3 years ago
Read 2 more answers
What is the ph of a 0.0055 m ha (weak acid) solution that is 8.2% ionized?
Trava [24]
Answer is: pH value of weak is 3.35.
Chemical reaction (dissociation): HA(aq) → H⁺(aq) + A⁻(aq).
c(HA) = 0.0055 M.
α = 8.2% ÷ 100% = 0.082.
[H⁺] = c(HA) · α.
[H⁺] = 0.0055 M · 0.082.
[H⁺] = 0.000451 M.
pH = -log[H⁺].
pH = -log(0.000451 M).
pH = 3.35.
pH (potential of hydrogen) is a numeric scale used to specify the acidity or basicity <span>an aqueous solution.</span>
3 0
3 years ago
Write the balanced electrochemical reaction for when zinc reacts with a copper solution. Label what is being oxidized and what i
Fed [463]

The balanced equation would be Zn + Cu^{2+} ---- > Cu + Zn^{2+}

<h3>Electrochemical equations</h3>

Zn reacts with Cu solution according to the following equation:

Zn + Cu^{2+} ---- > Cu + Zn^{2+}

In the reaction, Cu^{2+} is reduced according to the following: Cu^{2+} + 2 e^- -- > Cu

While Zn is oxidized according to the following: Zn - 2e^- --- > Zn^{2+}

Thus, giving the overall equation of; Zn + Cu^{2+} ---- > Cu + Zn^{2+}

More oxidation-reduction equations can be found here: brainly.com/question/13699873

#SPJ1

5 0
2 years ago
A hydrogen halide diffuses 1.49 times faster than HBr. This hydrogen halide is
marysya [2.9K]

To solve this problem, we must assume ideal gas behaviour so that we can use Graham’s law:

vA / vB = sqrt (MW_B / MW_A)

where,

<span>vA = speed of diffusion of A  (HBR)</span>

vB = speed of diffusion of B (unknown)

MW_B = molecular weight of B (unkown)

MW_A = molar weight of HBr = 80.91 amu

 

We know from the given that:

vA / vB = 1 / 1.49

 

So,

1/1.49 = sqrt (MW_B / 80.91)

MW_B = 36.44 g/mol

 

Since this unknown is also hydrogen halide, therefore this must be in the form of HX.

HX = 36.44 g/mol , therefore:

x = 35.44 g/mol

 

From the Periodic Table, Chlorine (Cl) has a molar mass of 35.44 g/mol. Therefore the hydrogen halide is:

HCl

6 0
3 years ago
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