Answer:
3 volts
Explanation:
It is given that,
Magnetic field, B = 0.8 T
Length of a conducting rod, l = 50 cm = 0.5 m
Velocity of the conducting rod, v = 7.5 m/s
We need to find the magnitude of the emf induced in the rod when it is moving toward the right. When a rod is moved in a magnetic field, an emf is induced in it and it is given by :
Putting all the values,
So, the magnitude of the emf induced in the rod is 3 volts.
Answer:
The vapour pressure of water is great tah 50 than it is 10.
Answer:
(a) Stiffness is measured by Young modulus
(b) Strength is measured as tensile stress in force per unit area
(c) Ductility is measured by elongation and reduction of area.
(d) Toughness is measured by the amount of energy that a unit volume of the material has absorbed after being stressed up to the point of fracture.
(e) Hardness is obtained by measuring the size of the impression left by an indenter
Explanation:
Mechanical properties are helpful in determining whether or not a material can be produced in the desired shape and also resist the mechanical forces anticipated.
Given mechanical properties of metals and how they are measured is as follows:
(a) Stiffness is the ability of a material to resist deformation under stress. It is measured by Young modulus
(b) Strength is the ability of a material to resist the externally applied forces without breaking or yielding. It is measured as tensile stress in force per unit area
(c) Ductility is the property of a material enabling it to be drawn into a wire with the application of a tensile force. It is measured by elongation and reduction of area.
(d) Toughness is the property of a material to resist fracture due to high impact. It is measured by the amount of energy that a unit volume of the material has absorbed after being stressed up to the point of fracture.
(e) Hardness is the property of a metal, which gives it the ability to resist being permanently deformed, when a load is applied. It is obtained by measuring the size of the impression left by an indenter
Answer:
<h2>4000
</h2>
Explanation:
The temperature of 0.1 kg of liquid rises from 25°C to 50°C in 300 sec. Energy of 13,600 J was supplied during this time. Appartus was losing energy at the rate of 12 J/sec.
Let us assume the Specific heat capacity as 
.
As there is no state change from liquid to gas, only Specific heat capacity is involved. Also, work done is approximately zero because volume does not change much. So,
Energy gained = Energy required to rise the temperature
Energy gained by liquid = 
∴ Specific heat capacity of liquid = 4000 
Answer:
B. 9025 J/s
Explanation:
thickness (d) = 0.367 cm = 0.00367 m
area (A) = 1.247 m^{2}
temperature difference (ΔT) =33.2 °C
thermal conductivity (K) = 0.8 J/s/m/°C
find the rate of heat flow
rate of heat flow = 
rate of heat flow = 
rate of heat flow = 9024.6 ≈ 9025 J/s
