The part of the eye that's similar to the film of a camera is the A. retina. B. cornea. C. iris. D. optic nerve.
2 answers:
The retina functions as a shadow catcher as in the film plate on the camera
<h3><em>Further explanation </em></h3>Several analog camera functions are almost the same as the functions in our eyes
- 1. Aperture on the camera functions as a place of entry of light, this is the same as the function of the cornea in the eye which is located in the outer part of the eye
- 2. Convex lenses on the camera function as shaper shadows just like a lens from the eye that serves to focus the light so that the image of the object just falls in the right position
- 3. The camera diaphragm functions to regulate the amount of light that affects the film, similar to the function of the pupil of the eye to regulate a lot of light entering
- 4. Plat film as a shadow catcher formed the convex lens of the camera, the same as the retina function of the eye which is located in the innermost part of the eye and has a receptor as a recipient of light
So the correct answer is retina (A)
<h3><em>Learn more </em></h3>
The part of the eye
our eye function
a characteristic of the cones in the eye
The iris in the human eye
Keywords: parts of the eye, retina, pupils, cornea, eye lens, diaphragm, film plate, camera
You might be interested in
Lewis Structure is drawn in following steps,
1) Calculate Number of Valence Electrons:
# of Valence electrons in Mg = 2
# of Valence electrons in I = 7
# of Valence electrons in I = 7
---------
Total Valence electrons = 16
2) Draw Mg as a central atom surround it by two atoms of Iodine.
3) Connect each Iodine atom to Mg, and subtract two electrons per bond. In this case we will subtract 4 electrons from total valence electrons. i.e.
Total Valence electrons 16
- Four electrons - 4
----------
12
4) Now start adding the remaining 12 electrons on more electronegative atoms i.e. Iodine.
The final lewis structure formed is as follow,
1) Calculate Number of Valence Electrons:
# of Valence electrons in Mg = 2
# of Valence electrons in I = 7
# of Valence electrons in I = 7
---------
Total Valence electrons = 16
2) Draw Mg as a central atom surround it by two atoms of Iodine.
3) Connect each Iodine atom to Mg, and subtract two electrons per bond. In this case we will subtract 4 electrons from total valence electrons. i.e.
Total Valence electrons 16
- Four electrons - 4
----------
12
4) Now start adding the remaining 12 electrons on more electronegative atoms i.e. Iodine.
The final lewis structure formed is as follow,