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3 years ago

What information does DNA provide to all of the cell's organelles

Chemistry

2 answers:

mr_godi [17]3 years ago

4 0

It gives each organelle in the cell its own specific function

Katena32 [7]3 years ago

4 0

Answer:

The correct answer will be- instructions to from proteins which perform different functions in the cell.

Explanation:

DNA is known as the genetic material of the cell as it stores the information required by the cell to survive.

The instructions in the DNA are stored in the form of "codons" which are made up of the triplets of the nitrogenous bases which when read during the process of translation in the ribosome codes for proteins.

These proteins perform different structural and metabolic functions in the cell and thus, instructions to from proteins which perform different functions in the cell are the correct answer.e proteins perform different structural and metabolic functions in the cell and thus, instructions to from proteins which perform different functions in the cell are the correct answer.

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Which of the following is a true

Katarina [22]

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3 years ago

can someone please help me with this question for chemistry. What is the number of moles in 1216 g Sr3(PO4)2? the 3,4, and 2 and

Alisiya [41]

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3 years ago

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3 years ago

Read 2 more answers

How many hydrogen atoms are in 5.80 mol of ammonium sulfide

IRINA_888 [86]

Moles of ammonium sulfide = 5.80 mol

The formula of ammonium sulfide is (NH₄)₂S

So each molecule of ammonium sulfide has (4 x 2) or 8 atoms of H

One mole of ammonium sulfide has 8 moles of H

5.80 mol of ammonium sulfide has (8 x 5.8) or 46.4 moles of H

As per the definition of Avogadro's number, 1 mole = 6.022 x 10²³ atoms

46.4 moles of H x (6.022 x 10²³ atoms/ 1 mole of H)

= 2.8 x 10²⁵ H atoms

Therefore, 2.8 x 10²⁵ H atoms are in 5.80 mol of ammonium sulfide.

5 0

3 years ago

You are given a solid that is a mixture of na2so4 and k2so4.

Murljashka [212]

Here we have to calculate the amount of $SO_{4}^{2-}$ ion present in the sample.

In the sample solution 0.122g of $SO_{4}^{2-}$ ion is present.

The reaction happens on addition of excess BaCl₂ in a sample solution of potassium sulfate (K₂SO₄) and sodium sulfate [(Na)₂SO₄] can be written as-

K₂SO₄ = 2K⁺ + $SO_{4}^{2-}$

(Na)₂SO₄=2Na⁺ + $SO_{4}^{2-}$

Thus, BaCl₂+ $SO_{4}^{2-}$ = BaSO₄↓ + 2Cl⁻ .

(Na)₂SO₄ and K₂SO₄ is highly soluble in water and the precipitation or the filtrate is due to the BaSO₄ only. As a precipitation appears due to addition of excess BaCl₂ thus the total amount of $SO_{4}^{2-}$ ion is precipitated in this reaction.

The precipitate i.e. barium sulfate (BaSO₄)is formed in the reaction which have the mass 0.298g.

Now the molecular weight of BaSO₄ is 233.3 g/mol.

We know the molecular weight of sulfate ion ( $SO_{4}^{2-}$ ) is 96.06 g/mol. Thus in 1 mole of BaSO₄ 96.06 g of $SO_{4}^{2-}$ ion is present.

Or. we may write in 233.3 g of BaSO₄ 96.06 g of $SO_{4}^{2-}$ ion is present. So in 1 g of BaSO₄ $\frac{96.06}{233.3}=0.411$ g of $SO_{4}^{2-}$ ion is present.

Or, in 0.298 g of the filtered mass (0.298×0.411)=0.122g of $SO_{4}^{2-}$ ion is present.

5 0

3 years ago