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2 years ago

Help me out w this plz

Chemistry

1 answer:

zhannawk [14.2K]2 years ago

4 0

Cant see the picture

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Iron forms rust, expressed as Fe2O3.

Elina [12.6K]

Answer:

it's C. 159.70 g

Explanation:

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2 years ago

Help me find the word elliptical

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2 years ago

A student prepares a solution of Potassium Nitrate (KNO3) containing 95g at 40 C. This solution is -

Sholpan [36]

Answer:

unsaturated

Explanation:

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1 year ago

Identify and label the Brønsted-Lowry acid, its conjugate base, the Brønsted-Lowry base, and its conjugate acid in each of the f

julia-pushkina [17]

Explanation:

As per Brønsted-Lowry concept of acids and bases, chemical species which donate proton are called Brønsted-Lowry acids.

The chemical species which accept proton are called Brønsted-Lowry base.

(a) $HNO_3 + H_2O \rightarrow H_3O^+ + NO_3^-$

$HNO_3$ is Bronsted lowry acid and $NO_3^-$ is its conjugate base.

$H_2O$ is Bronsted lowry base and $H_3O^+$ is its conjugate acid.

(b)

$CN^- + H_2O \rightarrow HCN + OH^-$

$CN^-$ is Bronsted lowry base and HCN is its conjugate acid.

$H_2O$ is Bronsted lowry acid and $OH^-$ is its conjugate base.

(c)

$H_2SO_4 + Cl^- \rightarrow HCl + HSO_4^-$

$H_2SO_4$ is Bronsted lowry acid and $HSO_4^-$ is its conjugate base.

Cl^- is Bronsted lowry base and HCl is its conjugate acid.

(d)

$HSO_4^-+OH^- \rightarrow SO_4^{2-}+H_2O$

$HSO_4^-$ is Bronsted lowry acid and $SO_4^{2-}$ is its conjugate base.

OH^- is Bronsted lowry base and $H_2O$ is its conjugate acid.

(e)

$O_{2-}+H_2O \rightarrow 2OH^-$

$O_{2-}$ is Bronsted lowry base and OH- is its conjugate acid.

$H_2O$ is Bronsted lowry acid and OH- is its conjugate base.

6 0

3 years ago

What is the mass of a magnesium block that measures 2.00 cm

skad [1K]

Answer:

m = 31.284 grams

Explanation:

Given that,

The dimension of a magnesium block is 2.00 cm x 3.00 cm x 3.00 cm.

The density of magnesium is, d = 1.738 g/cm³

We need to find the mass of the magnesium block. We know that the density of an object is given by its mass per unit its volume. So,

$d=\dfrac{m}{V}\\\\\text{Where m=mass}\\\\m=d\times V\\\\m=1.738\ g/cm^3\times (2\times 3\times 3)\ cm^3\\\\m=31.284\ \text{grams}$

So, the mass of the block is 31.284 grams.

5 0

2 years ago