Time = (distance) / (speed)
Time = (150 x 10⁹ m) / (3 x 10⁸ m/s) =
50 x 10¹ sec =
<em>500 sec</em> = 8 min 20 sec
Answer:
727.67 km
Explanation:
Sine they have Same distance D
distance = speed * time
D = 5.08t
D = 8.3312(t+55.9)
so
5.08t = 8.3312(t+55.9) t in
3.2512t = 465.71
t = 143.2s
Subtitute t
D=5.08 t
= 5.08 × 143.2
= 727.67km
Answer:
Image distance is -52.5 cm
Image is virtual and forms on the same side of the lens and upright image is formed.
Explanation:
u = Object distance
v = Image distance
f = Focal length = 35
m = Magnification = 2.5
Lens equation
Image distance is -52.5 cm
Image is virtual and forms on the same side of the lens and upright image is formed.
Answer:
a. F = 245 Newton.
b. Workdone = 392 Joules.
c. Power = 196 Watts
Explanation:
Given the following data;
Mass = 25kg
Distance = 1.6m
Time = 2secs
a. To find the force needed to lift the mass (in N );
Force = mass * acceleration
We know that acceleration due to gravity is equal to 9.8
F = 25*9.8
F = 245N
b. To find the work done by the student (in J);
Workdone = force * distance
Workdone = 245 * 1.6
Workdone = 392 Joules.
c. To find the power exerted by the student (in W);
Power = workdone/time
Power = 392/2
Power = 196 Watts.
Answer:
11320.63 Pa
Explanation:
= Pressure the heart is pumping at = (assumed)
= Density of blood = 1060 kg/m³
g = Acceleration due to gravity = 9.81 m/s²
h = Height = 0.45 m
From Bernoulli's equation we have
The pressure in the artery is 11320.63 Pa