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Elanso [62]
4 years ago
9

What is the potential difference vab between points a and b when the switch s is open?

Physics
1 answer:
juin [17]4 years ago
3 0
Assuming is a closed circuit when the switch is closed, it would be the strength of the battery in the circuit, assuming a and b were points at each end of the circuit. Depending on the specifics of the circuit, this could change, you could add more batteries together or it could reduce based on resistance if there's a viable current path still open while the switch is open. You may have missed attaching a picture or link.
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What is the smallest thing in universe ?​
Readme [11.4K]

Answer:

Explanation:

Physicists have found the latter- that matter is made of fundamental particles, the smallest things in the universe. Particles interact with each other according to a theory called the “Standard Model”. ... The electron is, as far as we know, one of the fundamental, indivisible building blocks of the universe

6 0
3 years ago
Which of the following lists are all renewable resources?
earnstyle [38]

The answer is A.

Hydroelectric, which is usually generating electricity through use of a dam.

Solar, energy from the Sun.

Biomass, organic material formed from plant matter.

3 0
3 years ago
Calculate the electric field at the location of a charge if the electric force is 10 newtons and the charge on the particle is 6
kolezko [41]

I think it may be c, 1.7 v. I work with electricity a lot.


6 0
3 years ago
Io, a satellite of Jupiter, is the most volcanically active moon or planet in the solar system. It has volcanoes that send plume
Mamont248 [21]

Answer:

1331.84 m/s

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity = 0

s = Displacement = 490 km

a = Acceleration

g = Acceleration due to gravity = 1.81 m/s² = a

From equation of linear motion

v^2-u^2=2as\\\Rightarrow -u^2=2as-v^2\\\Rightarrow u=\sqrt{v^2-2as}\\\Rightarrow u=\sqrt{0^2-2\times -1.81\times 490000}\\\Rightarrow u=1331.84\ m/s

The speed of the material must be 1331.84 m/s in order to reach the height of 490 km

3 0
4 years ago
Read 2 more answers
At a particular instant, a proton at the origin has velocity < 5e4, -2e4, 0> m/s. You need to calculate the magnetic field
vesna_86 [32]

Answer:

9.7\times 10^{-5} T

Explanation:

Velocity =5\times 10^4i-2\times 10^4j

r=0.03i+0.05j

r=\mid r\mid=\sqrt{(0.03)^2+(0.05)^2}=0.058

v=\mid V\mid=\sqrt{(5\times 10^4)^2+(-2\times 10^{4})^2}=5.39\times 10^{2}

We know that

B=\frac{mv}{qr}

Where q=1.6\times 10^{-19} C

Mass of proton=1.67\times 10^{-27} kg

Using the formula

B=\frac{1.67\times 10^{-27}\times 5.39\times 10^2}{1.6\times 10^{-19}\times 0.058}

B=9.7\times 10^{-5} T

3 0
3 years ago
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