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Anika [276]
3 years ago
10

Who was the first person to discover the existence of electrons​

Chemistry
2 answers:
nignag [31]3 years ago
6 0

Answer:

JJ Thomson was the first person to discover the existence of electrons. Although Julius plucker in 1859 observed electrons he couldn't specify his observations instead Thomson was the one who further studied plucker observations and specified it as electrons..

k0ka [10]3 years ago
4 0
Electron was discovered by J. J. Thomson in 1897 when he was studying the properties of cathode ray.
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What is a responding variable
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A manipulated variable is also called an independent variable. A responding variable is a variable that the researcher predicts will change if the manipulated variable changes. A responding variable is also called a dependent variable.

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3 years ago
a 2000ml bottle has a mass of 234g when empty and a mass of 2367g when full of pop. how dense is the pop that is in the bottle
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density = mass/volume sub the values

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What is the job of an environmental engineer?
xz_007 [3.2K]

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To keep the evinermental machinces working

Explanation:

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3 years ago
Which of the following is the most recent addition to the accepted model of the atom? (2 points) Atoms are indivisible particles
Georgia [21]
The accepted model of an atom was made by Schrodinger, which is known as the quantum mechanical model. Unlike Bohr's model, electrons are represented as a cloud and not small balls orbiting the nucleus. There is no define path of electrons in Schrodinger's model, but it can predict the odds of where an electron is located. 

The answer to your question is then Electrons form a cloud around the nucleus.
5 0
3 years ago
Read 2 more answers
How many ions of aluminum oxide (Al²O³) are there in 200 g of Al²O³??<br><br>​
valentinak56 [21]

= 6.022 × 1020

Explanation<em>;</em>

Mole of aluminium oxide (Al2O3) is

⇒ 2 x 27 + 3 x 16

Mole of aluminium oxide = 102 g

i.e., 102 g of Al2O3= 6.022 x 1023 molecules of Al2O3

Then, 0.051 g of Al2O3 contains = 6.022 x 1023 / (102 x 0.051 molecules)

= 3.011 x 1020 molecules of Al2O3

The number of aluminium ions (Al3+) present in one molecule of aluminium oxide is 2.

Therefore, the number of aluminium ions (Al3+) present in 3.11 × 1020 molecules (0.051g) of aluminium oxide (Al2O3)

= 2 × 3.011 × 1020

=<em> 6.022 × 1020</em>

<em>hope </em><em>it </em><em>helps</em><em>_</em>

6 0
2 years ago
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