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Nezavi [6.7K]
3 years ago
12

An archer pulls her bowstring back 0.226 m by exerting a force that increases uniformly from zero to 263 N. What is the equivale

nt spring constant of the bow?
Physics
2 answers:
enyata [817]3 years ago
7 0

Answer: k = 1163.72 N/m²

Explanation: if the bow obeys hook's law, then force is proportional to extension.

F = ke.

F= Force = 263 N

k = force constant

e = extension = 0.226m

263 = k * 0.226

k = 263/ 0.226

k = 1163.72 N/m²

Georgia [21]3 years ago
6 0
<h2>Answer:</h2>

1163.7N/m

<h2>Explanation:</h2>

When a force caused by an object is applied to a spring, the spring applies an equal and opposite force to that object. This is evident in Hooke's law which states that the force(F) applied to a spring, either to cause extension or compression, is directly proportional to the length of the extension or compression (x). i.e

F = k x            ---------------------(i)

Where k is the proportionality constant called <em>spring constant.</em>

<em />

<em>Given;</em>

F = force exerted on the bowstring = 263N

x = length of extension = 0.226m

<em>Substitute these values into equation (i) as follows;</em>

263 = k (0.226)

<em>Solve for k;</em>

k = 263 / 0.226

k = 1163.7N/m

Therefore, the spring constant of the bow is 1163.7N/m

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A person walked 30.0 m east and then 100.0 m north. Add these two vectors to get the magnitude of the vector sum of the two move
lakkis [162]

Answer:

D = 104.4 m

Explanation:

We are given two displacement vectors. One in north direction other in east direction. We know that north and east directions are perpendicular to each other. Hence, the displacements vectors are also perpendicular to each other. Therefore, there resultant can be found by using Pythagora's Theorem like rectangular components method.

D = √(Dₓ² + Dy²)

where,

D = Magnitude of vector sum of both displacements = ?

Dₓ = Magnitude of Displacement Vector in east direction = 30 m

Dy = Magnitude of Displacement Vector in North Direction = 100 m

Therefore,

D = √[(30 m)² + (100 m)²]

<u>D = 104.4 m</u>

7 0
3 years ago
a vertical solid steel post 29cm in diameter and 2.0m long is required to support a load of 8200kg, ignore the weight of the pos
erik [133]

Answer:

The stress is  \sigma  =  1.218*10^{6} \  N/m^2

Explanation:

From the question we are told that

   The diameter of the post is  d =  29 \ cm  =  0.29 \  m

   The length is L  =  2.0 \  m

    The weight of the loading mass

Generally  the  radius of the post is mathematically represented as

     r =  \frac{0.29}{2}

=>   r = 0.145 \  m

Generally the area of the post is  

       A =  \pi r^2

=>     A =  3.14 *  0.145 ^2

=>     A =  0.066 \ m^2

Generally the weight exerted by the load is mathematically represented as

        F =  m  *  g

=>      F =  8200  *  9.8

=>      F =  80360 \  N

Generally the stress is mathematically represented as

         \sigma  =  \frac{F}{A}

=>      \sigma  =  \frac{80360 }{0.066}

=>      \sigma  =  1.218*10^{6} \  N/m^2

7 0
2 years ago
An object has 16N of force being applied to the right, 16N of force being applied to the left, and 4N of force being applied dow
goldenfox [79]

Answer:

4N downward

Explanation:

the 16N left and right cancel each other out, so you are left with the 4N downward.

6 0
3 years ago
Which property increases as an electromagnetic wave's energy decreases?
aleksklad [387]
The answer is B frequency. When frequency increases more wave crests pass a fixed point each second. That means the wavelength shortens. So, as frequency increases, wavelength decreases
4 0
3 years ago
Bob walks 370 m south, then jogs 410 m southwest, then walks 370 m in a direction 28 degrees east of north.
wlad13 [49]
We will measure all angles from West, the negative x-axis and divide the journey into 3 parts:
P1 = 370y
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Overall displacement:
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y = 370 + 290 - 327 = 333 m

displacement = √(116² + 333²)
= 353 m

Direction:
tan(∅) = y/x
∅ = tan⁻¹ (333 / 116)
∅ = 70.8° from West.
5 0
3 years ago
Read 2 more answers
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