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marissa [1.9K]
3 years ago
15

CAN ANYONE ELP ME WITH CHEMISTRY PLEASE?? I will be asking multiple questions but even if you can only answer one-- I will still

deeply appreciate it!!! (These are the one's Im unsure about..)
3. Identify the reducing agent in the following equation: 2 Al(s) + 3 H2SO4 (aq) arrow Al2(SO4)3 (aq) + 3 H2 (g).

A. Al (s) *
B. H2SO4 (aq)
C. Al2(SO4)3 (aq)
D. H2 (g)

9. How many milliliters are 0.200 M HCl are required to react completely with 25.0 milliliters of 0.100 M methylamine, CH3NH2?

A. 5.00 ml
B. 6.25 ml
C. 12.5 ml *
D. 25.0 ml

16. A solution has a [OH−] of 1 x 10−9. What is the pOH of this solution?

A. 5
B. 7
C. 9 *
D. 12

17. If a small amount of excess acid is added to a buffered solution, the pH of the solution should:

A. change sharply and then neutralize *
B. remain very close to the original pH value
C. fluctuate rapidly between high and low values and then achieve a neutral balance
D. neutralize instantaneously

18.Compared to other main group hydrides, such as CH4, NH3, H2S and HF, water is unique because it is a liquid at room temperature. The most likely explanation for this is that:

A. Water is more plentiful than any of these other compounds.
B. Water contains oxygen and since oxygen has a high boiling point, so should water.
C. Water's structure allows for the formation of multiple hydrogen bonds with other molecules, including itself. *
D.Water is able to dissolve nonpolar gases like oxygen and carbon dioxide.

28. Predict whether the following double-replacement reaction will produce a precipitate: MgCl2 + Li2CO3 arrow MgCO3 + 2 LiCl.

A.No; all products are soluble
B. Yes; the MgCO3 will precipitate *
C.Yes; the LiCl will precipitate
D. Yes; both the MgCO3 and the LiCl will precipitate

BTW I added a * to the answers I THINK are correct.
Chemistry
1 answer:
vlabodo [156]3 years ago
6 0
3, 9, 16 are correct! 17 should be b because buffered means that it resists change in pH
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What is the molecular formula for a compound that has the empirical formula of hgcl and a molar mass of 472.2g/mol?
garri49 [273]
This problem is quite easy once you start thinking about it.

If the empirical formula is HgCl (which has a molar mass of 271.5 g/mol)

And the molar mass of the molecular compound is 472.2 g/mol, just divide the two numbers. You'll get 1.74. And since this number is a decimal, this question isn't solvable. You've either provided the wrong empirical formula or the wrong molar mass. 
4 0
3 years ago
Names for following compounds.<br> a)CO²<br> b)NaCI<br> c)S²CI²<br> d)NaF
babymother [125]
  • <em>Co²</em><em> </em><em>=</em><em> </em><em>Carbon</em><em> dioxide</em>
  • <em>NaCl </em><em>=</em><em> </em><em> </em><em>Sodium </em><em>Chloride</em>
  • <em>S²</em><em>C</em><em>l</em><em>²</em><em> </em><em>=</em><em> </em><em> </em><em>Sulphur </em><em>Chloride</em>
  • <em>NaF </em><em>=</em><em> </em><em>Sodium</em><em> </em><em>Fluoride</em>

5 0
3 years ago
2. How many moles of fluorine are required to produce 12.0 grams of
LuckyWell [14K]

Answer:

0.0984mol of F2

Explanation:

The equation for the reaction is given below:

Kr + F2 → KrF2

Let us convert 12g of KrF2 to mole. This is illustrated below

Molar Mass of KrF2 = 84 + (2x19) = 84 + 38 = 122g/mol

Mass of KrF2 = 12g

Number of mole = Mass /Molar Mass

Number of mole of KrF2 = 12/122 = 0.0984mol

From the equation,

1mole of F2 produced 1mole of KrF2.

Therefore 0.0984mol of F2 will produce 0.0984mol of KrF2

7 0
3 years ago
The km of an enzyme is 5. 0 mm. Calculate the substrate concentration when this enzyme operates at one‑quarter of its maximum ra
Makovka662 [10]

The substrate concentration of the enzyme operating at one‑quarter of its maximum rate is = 0.333.

Relationship between Km and substrate concentration is -

Km is the concentration of substrate.It allows the enzyme to achieve half Vmax. High Km enzyme requires a higher concentration of substrate to get Vmax. Since, Km is a constant. If the substrate concentration is increased, it has no effect on it.

An enzyme with a high Km has a low affinity for its substrate. The substrate concentration Km corresponds to the substrate concentration.

The substrate concentration at which the reaction rate of the enzyme-catalyzed reaction is half of the maximum reaction rate Vmax.

The equation is:

                <em>V₀ = </em><u><em>Vmax [S] </em></u>

<em>                          [S] + Km</em>

Here,

V₀ is initial rate,

Km is the dissociation constant between the substrate and the enzyme,

Vmax is the maximum rate, and

S is the concentration of substrate.

taking fraction of V₀ and Vmax :

<u><em>    V₀    </em></u><em> = </em><u><em>     [S</em></u><em>]</em><u><em>     </em></u><em>  </em>

<em>Vmax      [S] + Km</em>

<u><em>   </em></u><u>V₀   </u> =   <u>   0.5Km   </u>  = 0.333

Vmax       1.50 + Km

Therefore, the substrate concentration of this enzyme operating at one‑quarter of its maximum rate is = 0.333.

To learn more about substrate concentration,

brainly.com/question/18237939

#SPJ4

3 0
11 months ago
Why can hydrogen only form one covalent bond?
MrRa [10]
Because its in group one....which only lose or gain electrons.....thus it will only have oneelectron to fulfill its octect rule
7 0
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