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Sever21 [200]
3 years ago
8

PLZ HELP ME FAST I WILL GIVE BRAINLIST!! Two vehicles are traveling down the highway going 40 mph. Which has more kinetic energy

and why? A 2000kg car going 40 mph A 4000 kg bus going 40 mph Explain:
Chemistry
2 answers:
Mars2501 [29]3 years ago
5 0
They actually have the same amount of kinetic energy but the bus I would say is more cuz it weighs more mass, more mass means the more energy it's going to need.
Degger [83]3 years ago
4 0

A 4000 kg bus going 40 mph has more kinetic energy than a 2000kg car going 40 mph. tis cuz' KE=1/2*mass*velocity^2 so bus has higher 2x mass of car n 2x KE, even thou their speed is the same.

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chegg 2. What pattern did you observe measuring cell voltages with a silver electrode versus with a platinum/H2 electrode
Eduardwww [97]

chegg 2. What pattern did you observe measuring cell voltages with a silver electrode versus with a platinum/H2 electrode There is a difference of -0.786 V in silver

<h3>What is cell voltages ?</h3>

The difference in electric potential between two points, also known as voltage, electric potential difference, electric pressure, or electric tension, is what determines how much labor is required to move a test charge between the two sites in a static electric field. Volt is the name of the derived unit for voltage (potential difference) in the International System of Units. Joules per coulomb, or 1 volt equals 1 joule (of work) for 1 coulomb, is how work per unit charge is stated in SI units (of charge). The quantum Hall and Josephson effect was first employed in the 1990s, and most recently (in 2019), fundamental physical constants have been added for the definition of all SI units and derived units. Power and current were used in the previous SI definition for volt.

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brainly.com/question/18938125

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7 0
2 years ago
What characterizes an Arrhenius base?
dybincka [34]

Answer:

An Arrhenius base is a substance that dissociates in water to form hydroxide (OH–) ions. In other words, a base increases the concentration of OH– ions in an aqueous solution.

7 0
2 years ago
State of matter is the least In general, for any material, the compressible. ​
mihalych1998 [28]

Answer:

Bulk matter can exist in three states: gas, liquid, and solid. Gases have the lowest density of the three, are highly compressible, and fill their containers completely

Explanation:

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6 0
3 years ago
Given: A(g) + B(g) ⇋ C(g) + D(g) At equilibrium a 2.00 liter container was found to contain 1.60 moles of C, 1.60 moles of D, 0.
Alexandra [31]

Answer:

Kc = 10.24

Q = 9.07

[A] = 0.262 mol/L

Explanation:

In a reversible reaction, the equilibrium occurs when the velocity of the formation of the products is equal to the velocity of the formation of the reactants. When this happens, the concentrations remain constant. The ratio between the multiplication of the concentration of the products by the multiplication of the reactants (each concentration elevated by the substance's coefficient) is called Kc, the equilibrium constant.

The value of the Kc depends on the temperature, and the pure liquids and solids are considered to have concentration equal to 1 (because it's activity is equal to 1, and the activity is aproximated to the concentrantion). So, for the reaction given, the concentrations at the equilibrium are:

[A] = 0.50 moles / 2.00 liter = 0.25 mol/L

[B] = 0.50 moles / 2.00 liter = 0.25 mol/L

[C] = 1.60 moles / 2.00 liter = 0.80 mol/L

[D] = 1.60 moles / 2.00 liter = 0.80 mol/L

Kc = [C]*[D]/[A]*[B]

Kc = 0.8*0.8/0.25*0.25

Kc = 0.64/0.0625

Kc = 10.24

The value of Q, the reaction quotient, is calculated as the value of Kc, but now, with the concentrations at a certain time and not necessariy in equilibrium. The new concentrantions of B and C will be:

[B] = (0.50 + 0.10)/2.00 = 0.3 mol/L

[C] = (1.60 + 0.10)/2.00 = 0.85 mol/L

Q = [C]*[D]/[A]*[B]

Q = 0.85*0.8/0.25*0.3

Q = 0.68/0.075

Q = 9.07

Because more product was added, by the Le Chatelier's principle, the reaction will shift in order to consume C and D, and forms more A and B, and so the equilibrium will be achieved again, so, let's do an equilibrium chart:

A(g) + B(g) ⇄ C(g) + D(g)

0.25   0.3      0.85    0.8        Initial

+x       +x         -x        -x          Reacts (stoichiometry is 1:1:1:1)

0.25+x  0.3+x  0.85-x 0.8-x  Equilibrium

Kc = (0.85-x)*(0.8-x)/(0.25+x)*(0.3+x)

10.24 = (0.68 - 1.65x + x²)/(0.075 + 0.55x + x²)

10.24x² + 5.632x + 0.768 = 0.68 - 1.65x + x²

9.24x² + 7.282x - 0.088 = 0

Solving by a graphic calculator, and knowing that x > 0 and x < 0.8

x = 0.012 mol/L

So, [A] = 0.25 + 0.012 = 0.262 mol/L

6 0
3 years ago
Predict which of the following pairs of solutions, when mixed together, will cause a precipitate to form. (Select all that apply
Kay [80]

Answer:

25 mL of 1 × 10–5 M Co(NO₃)₂ and 75 mL of 5 × 10–4 M Na₂S

500 mL of 7.5 × 10–4 M AlCl₃ and 100 mL of 1.7 × 10–5 M Hg₂(NO₃)₂.

650 mL of 0.0080 M K₂SO₄ and 175 mL of 0.15 M AgNO₃

Explanation:

When 2 compounds that produce an insoluble substance are mixed together, <em>A precipitate will be formed if Q of reaction > Ksp</em>

For the solutions:

1.5 L of 0.025 M BaCl₂ and 1.25L of 0.014 M Pb(NO₃)₂.

Ksp is:

PbCl₂(s) ⇄ Pb²⁺(aq) + 2Cl⁻(aq)

Ksp = 2.4x10⁻⁴ = [Pb²⁺][Cl⁻]²

Molar concentration of each ion is:

[Pb²⁺] =  1.25L ₓ (0.014mol / L) = 0.0175mol / 2.75L = 6.36x10⁻³M

[Cl⁻] = 2 ₓ 1.5L ₓ (0.025mol / L) = 0.075mol / 2.75L = 0.0273M

Replacing in Ksp expression to find Q:

Q = [6.36x10⁻³M][0.0273M]² = 4.73x10⁻⁶

As Q < Ksp, the mixture will not produce a precipitate.

25 mL of 1 × 10–5 M Co(NO₃)₂ and 75 mL of 5 × 10–4 M Na₂S

Ksp is:

CoS(s) ⇄ Co²⁺(aq) + S²⁻(aq)

Ksp = 4.0x10⁻²¹ = [Co²⁺][S²⁻]

Molar concentration of each ion is:

[Co²⁺] =  0.025L ₓ (1x10⁻⁵mol / L) = 2.5x10⁻⁷mol / 0.1L = 2.5x10⁻⁶M

[S²⁻] = 0.075L ₓ (5x10⁻⁴mol / L) = 3.75x10⁻⁵mol / 0.1L = 3.75x10⁻⁴M

Replacing in Ksp expression to find Q:

Q = [2.5x10⁻⁶M][3.75x10⁻⁴M] = 9.38x10⁻⁶

As Q > Ksp, the mixture will produce a precipitate.

500 mL of 7.5 × 10–4 M AlCl₃ and 100 mL of 1.7 × 10–5 M Hg₂(NO₃)₂.

Ksp is:

Hg₂Cl₂(s) ⇄ 2Hg⁺(aq) + 2Cl⁻(aq)

Ksp = 3.5x10⁻¹⁸ = [Hg⁺]²[Cl⁻]²

Molar concentration of each ion is:

[Hg⁺] =  2ₓ0.100L ₓ (1.7x10⁻⁵mol / L) = 3.4x10⁻⁶mol / 0.6L = 5.67x10⁻⁶M

[Cl⁻] = 3 ₓ 0.500L ₓ (7.5x10⁻⁴mol / L) = 1.125x10⁻³mol / 0.6L = 1.88x10⁻³M

Replacing in Ksp expression to find Q:

Q = [5.67x10⁻⁶M]²[1.88x10⁻³M]² = 1.14x10⁻⁶

As Q > Ksp, the reaction will produce a precipitate.

650 mL of 0.0080 M K₂SO₄ and 175 mL of 0.15 M AgNO₃

Ksp is:

Ag₂SO₄(s) ⇄ 2Ag⁺(aq) + SO₄²⁻(aq)

Ksp = 1.5x10⁻⁵ = [Ag⁺]²[SO₄²⁻]

Molar concentration of each ion is:

[Ag⁺] =  0.175L ₓ (0.15mol / L) = 0.02625mol / 0.825L = 0.0318M

[SO₄²⁻] = 0.650L ₓ (0.080mol / L) = 0.052mol / 0.825L = 0.0630M

Replacing in Ksp expression to find Q:

Q = [0.0318M]²[0.0630M] = 6.37x10⁻⁵

As Q > Ksp, the reaction will produce a precipitate.

6 0
3 years ago
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