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melisa1 [442]
3 years ago
7

A rowboat passenger uses an oar to push the boat off the dock by exerting a force of 60.0 N for 2.0s. What impulse acts on the b

oat?
Physics
1 answer:
NARA [144]3 years ago
6 0
Impulse<span> is the change of momentum of an object when the object is acted upon by a force for an interval of time. It is simply calculated by the expression:
</span>
Impulse = F(change in time)
Impulse = 60(2)
Impulse = 120 Ns

Hope this answers the question. Have a nice day.
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Explain how energy allows a paper clip to be attracted to a magnet
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I really don’t know maybe energy from the poles just attaches and the soil comes and energy lifts the matter of soil and the magnet follows and lifts and goes up to the soil and the poles attach the magnet to the soil and the energy lifts the magnet and the soil follows and it is attracted to the magnet

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A car of mass 800kg travels a distance of 40m at constant speed in a duration of 2.0s. The car exerts a forward force of 15kN.
Alex17521 [72]

W = F × s

W = 15kN × 40 m

W = 15.000 N × 40 m

W = 600.000 J

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P = 600.000 J/2 s

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3 years ago
Experts, ACE, Genius... can anybody calculate for the Reactions at supports A and B please? Will give brainliest! Given: fb = 30
dybincka [34]

Answer:

Support at Cy = 1.3 x 10³ k-N

Support at Ay = 200 k-N

Explanation:

given:

fb = 300 k-N/m

fc = 100 k-N/m

D = 300 k-N

L ab = 6 m

L bc = 6 m

L cd = 6 m

To get the reaction A or C.

take summation of moment either A or C.

<em><u>Support Cy:</u></em>

∑ M at Ay = 0

      (( x1 * F ) + ( D * Lab ) + ( D * L bc + D * L cd )

Cy = -------------------------------------------------------------------

                                      ( L ab + L bc )

Cy = 1.3 x 10³ k-N

<em><u>Support Ay:</u></em>

Since ∑ F = 0,           A + C - F - D = 0

                                   A = F  + D - C

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3 years ago
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The maximum speed the mass can have before it breaks is 2.27 m/s.

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The maximum speed the mass can have before it breaks is calculated as follows;

T = ma_c\\\\Mg = \frac{Mv^2}{r} \\\\v^2 = rg\\\\v = \sqrt{rg} \\\\v_{max} = \sqrt{0.525 \times 9.8} \\\\v_{max} = 2.27 \ m/s

Thus, the maximum speed the mass can have before it breaks is 2.27 m/s.

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8 0
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c=Q/m∆T

where Q is energy .

note water has a higher specific heat, and lower temperature.

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