Answer:
awnser is true took the test
Explanation:
i took the test
Answer:
to VSEPR theory, the shape of a molecule is related to the organization of the central atom's valence shell electrons. The valence shell electrons are all negatively charged and therefore are constantly repelling each other. This repulsion is what gives a molecule its three-dimensional shape.
<span>The question is asking us "Which of the following would be a result of increased solar activity?"
The Sun is extremely hot, and when it is warm on Earth, the heat has as it source in the Sun. Therefore, an increased solar activity would mean increased temperature on Earth - longer summers and shorter winters, and warmer sea temperatures. The best answer is :
B. Warmer-than-normal sea surface temperatures </span>
Answer:
Compound X= 4-bromo-2,3,3-trimethylhexane
Compound Y= 5-chloro-2,3,3-trimethylhexane
Explanation:
The first step is set up the problem. That way we can obtain some clues. If we check figure 1 we can obtain some ideas:
-) If we have E2 reaction is not possible a <u>methyl or hydride shift</u>.
-) If we have an E2 reaction we will need an H in <u>anti position</u> to obtain the double bond. Therefore a double bond with the quaternary carbon (the carbon bonded to the 2 methyl groups).
The second step is to solve the alkene structure. We have to put the <u>leaving group</u> near to carbon that has more possible <u>removable hydrogens</u>. That's why the double bond is put it between carbons 5 and 4 of the alkane (Figure 2).
The third step is the structure of the <u>alkyl bromide</u> structure. To do this we have to check the alcohol produced by the alkene. In the <u>hydration of alkanes</u> reaction we will have a <u>carbocation</u> formation. Therefore we can have for the alkene proposed a methyl shift to obtain the most stable carbocation. With this in mind, we have to do the same for the Alkyl bromide that's why the Br is put it carbon 4 of the alkane. If we put the Br on this carbon we can have the chance of this <u>methyl shift</u> also, to obtain the same alcohol (figure 3).
Finally, for the <u>alkyl chloride</u>, we only have 2 choices because to produce the alkane we have to put the <u>leaving group</u> on one of the 2 carbons of the double bond. If we choose the same carbon on which we put the Br we can have the same behavior of the alkyl bromide (the <u>methyl shift</u>), therefore we have to put in the other carbon.