Which of the following is a solution? (2 points)

1 answer:

7 0

An alloy maybe could be used as a solid but i really don't think that would be it so i would sayether from an alloy or dirt

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The first step is set up the problem. That way we can obtain some clues. If we check figure 1 we can obtain some ideas:

-) If we have E2 reaction is not possible a methyl or hydride shift.

-) If we have an E2 reaction we will need an H in anti position to obtain the double bond. Therefore a double bond with the quaternary carbon (the carbon bonded to the 2 methyl groups).

The second step is to solve the alkene structure. We have to put the leaving group near to carbon that has more possible removable hydrogens. That's why the double bond is put it between carbons 5 and 4 of the alkane (Figure 2).

The third step is the structure of the alkyl bromide structure. To do this we have to check the alcohol produced by the alkene. In the hydration of alkanes reaction we will have a carbocation formation. Therefore we can have for the alkene proposed a methyl shift to obtain the most stable carbocation. With this in mind, we have to do the same for the Alkyl bromide that's why the Br is put it carbon 4 of the alkane. If we put the Br on this carbon we can have the chance of this methyl shift also, to obtain the same alcohol (figure 3).

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