Answer:
The answer is partial charge 8+.
Answer:
The right solution is "
".
Explanation:
As we know,
1 mole electron = ![6.023\times 10^{23} \ no. \ of \ electrons](https://tex.z-dn.net/?f=6.023%5Ctimes%2010%5E%7B23%7D%20%5C%20no.%20%5C%20of%20%5C%20electrons)
Total energy = ![513 \ KJ](https://tex.z-dn.net/?f=513%20%5C%20KJ)
= ![513\times 1000 \ joule](https://tex.z-dn.net/?f=513%5Ctimes%201000%20%5C%20joule)
For single electron,
The amount of energy will be:
= ![\frac{513\times 1000}{(6.023\times 10^{23})}](https://tex.z-dn.net/?f=%5Cfrac%7B513%5Ctimes%201000%7D%7B%286.023%5Ctimes%2010%5E%7B23%7D%29%7D)
= ![8.5\times 10^{-19} \ joule](https://tex.z-dn.net/?f=8.5%5Ctimes%2010%5E%7B-19%7D%20%5C%20joule)
The answer for this question is 0.8
Answer:
See Explanation
Explanation:
Metallic bonds involve attraction between electrons and positively charged metal ions. The metals are ionized and electrons form a sea of valence electrons. These loosely bound electrons surround the nuclei of the metals.
The presence of this sea of electrons explains the fact that metals conduct electricity and heat due to the free valence electrons.
Due to the nature of the bonding between metal atoms,metals are malleable and ductile.
Due to the strong electrostatic interaction between metal ions and electrons, the metallic bond is very strong and is very difficult to break thereby accounting for the greater strength of metals as the size of the metallic ion decreases.
Answer:
A beaker
Step-by-step explanation:
Specifically, I would use a 250 mL graduated beaker.
A beaker is appropriate to measure 100 mL of stock solution, because it's easy to pour into itscwide mouth from a large stock bottle.
You don't need precisely 100 mL solution.
If the beaker is graduated, you can easily measure 100 mL of the stock solution.
Even if it isn't graduated, 100 mL is just under half the volume of the beaker, and that should be good enough for your purposes (you will be using more precise measuring tools during the experiment).