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3 years ago

Help please help me

Chemistry

1 answer:

Alenkasestr [34]3 years ago

8 0

Answer: It completely dissociates in water is a characteristic of strong acid.

Explanation:

An acid which dissociates completely to give hydrogen ions $(H^{+})$ is called a strong acid.

For example, HCl is a strong acid and it dissociates completely as follows.

$HCl \rightleftharpoons H^{+} + Cl^{-}$

Strong acids are able to conduct electricity in water as more number of ions are present in the solution as compared to the ions present in a solution of weak acid.

Strong acids increase the concentration of $H^{+}$ ions.

Thus, we can conclude that it completely dissociates in water is a characteristic of strong acid.

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Answer:

The three gases, in the three identical containers, will all have the same number of molecules

Explanation:

If these three gases (Helium He, Neon Ne, and Oxygen $O_{2}$ ) are all contained in separate identical containers with the same volume. And they are all stored at the same temperature, and pressure. Then, they'll all contain the same number of molecules. This is in line with Avogadro's law which states that "Equal volume of all gases, at the same temperature and pressure, have the same number of molecules."

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3 years ago

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Answer:

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2 years ago

ASAP Would you expect the odor of an open bottle of perfume to spread through the air faster when the room temperature is 85F or

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Answer: The answer would be 85F

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3 years ago

A student has 70.5 mL of a 0.463 M aqueous solution of sodium bromide. The density of the solution is 1.22 g/mL. Find the follow

AleksandrR [38]

Answer:

a.) 86.01 g.

b.) 3.36 g.

c.) 0.394 m ≅ 0.40 m.

d.) 4.77%.

e.) 3.9%.

Explanation:

a.) mass of the solution:

The density of the solution is the mass per unit volume.

∵ Density of solution = (mass of solution)/(volume of the solution).

∴ Mass of the solution = (density of solution)*(volume of the solution) = (1.22 g/mL)*(70.5 mL) = 86.01 g.

b.) grams of sodium bromide :

Molarity (M) is defined as the no. of moles of solute dissolved per 1.0 L of the solution.

∵ M = (no. of moles of NaBr)/(Volume of the solution (L))

∴ no. of moles of NaBr = M*(Volume of the solution (L)) = (0.463 M )*(0.0705 L) = 0.0326 mol.

∵ no. of moles of NaBr = (mass of NaBr)/(molar mass of NaBr)

∴ mass of NaBr = (no. of moles of NaBr)*(molar mass of NaBr) = (0.0326 mol)*(102.894 g/mol) = 3.36 g.

c.) molality of the solution:

Molality (m) is defined as the no. of moles of solute dissolved per 1.0 kg of the solvent.

∵ m = (no. of moles of NaBr)/(mass of the soluvent (kg))

no. of moles of NaBr = 0.0326 mol,

mass of solvent = mass of the solution - mass of NaBr = 86.01 g - 3.36 g = 82.65 g = 0.08265 kg.

∴ m = (no. of moles of NaBr)/(mass of the soluvent (kg)) = (0.0326 mol)/(0.08265 kg) = 0.394 m ≅ 0.40 m.

d.) % (m/v) of the solution:

∵ (m/v)% = [(mass of solute) /(volume of the solution)]* 100

∴ (m/v)% = [(3.36 g)/(70.5 mL)]* 100 = 4.77%.

e.) % (m/m) of the solution:

∵ (m/m)% = [(mass of solute) /(mass of the solution)]* 100

∴ (m/m)% = [(3.36 g)/(86.01 g)] * 100 = 3.9 %.

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3 years ago

Which type of bond holds atoms together in a water molecule

Mashutka [201]

Hydrogen bonds together the atoms in a water molecule. Hope I helped!

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3 years ago

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