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stellarik [79]
3 years ago
7

HELP ASAP

Chemistry
2 answers:
Romashka [77]3 years ago
6 0

Answer:

1) 206 g /mol

2) 0.971 mmol or 9.71 X 10⁻⁴ mol

3) 7.768 mmol or 7.768 X 10⁻³ mol

Explanation:

1) Let us calculate the molar mass by adding the atomic mass of each atom present in the given ibuprofen molecule.

Molecular formula : C₁₃H₁₈O₂

Molar mass = 13 X atomic mass of C + 18X atomic mass of H +2 X atomic mass of O

Molar mass = 13 X 12 + 18X1 + 2X16 = 206g/mol

2) moles is calculated as:

moles=\frac{mass}{molarmass}=\frac{200mg}{206}=0.971mmol

This is the moles in each ibuprofen tablet.

3) Now in each dose there are two tablets.

The adult took four doses

The number of tablets taken = 4X2 = 8

the number of moles taken = 8X0.971 mmol = 7.768 mmol

Virty [35]3 years ago
5 0
 <span>To find the molar mass, look at a periodic table for each element. 
Ibuprofen, C13 H18 and O2. Carbon has a molar mass of 12.01 g, Hydrogen has 1.008 g per mole, and Oxygen is 16.00 g per mole. 

C: 13 * 12.01 
H: 18 * 1.008 
O: 2 * 16.00 
Calculate that, add them all together, and that is the molar mass of C13H18O2. 
Molar mass: 206.274 

Next, you have 200mg in each tablet, with a ratio of C13H18O2 (molar mass) in GRAMS per Mole 
So, you need to convert miligrams into grams, which is 200 divided by 1000. 
0.2 g / Unknown mole = 206.274 g / 1 Mole 

This is a cross multiplying ratio where you're going to solve for the unknown moles of grams per tablet compared to the moles per ibuprofen. 
So, it's set up as: 
0.2 g * 1 mole = 206.274 * x 
0.2 = 206.274x 
divide each side by 206.274 to get X alone 
X = 0.00097 
or 9.7 * 10^-4 moles 

The last problem should be easy to figure out now that you have the numbers. 1 dose is 2 tablets, which is the moles we just calculated above, times four for the dosage. 
</span>
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C₁₄H₂₂N₄O₈

Explanation:

To find the molecular weight of the compound C₁₄H₂₂N₄O₈ we simply sum that atomic masses of the given elements in the compound.

 The empirical weight is determined by using the simplest ratio of the elements involved in the compound;

Molecular weight of C₁₄H₂₂N₄O₈;

atomic mass of C = 12g/mol

                           H = 1g/mol

                            N = 14g/mol

                            O = 16g/mol

 Molecular weight = 14(12) + 22(1) + 4(14) + 8(16)

                                = 168 + 22 + 56 + 128

                                 = 374u

Empirical weight:

  Empirical formula:

                        C₁₄    H₂₂      N₄     O₈

                         14  :    22 :    4  :     8

   divide by 2:

                          7   :    11    :    2  :    4

     empirical formula  C₇H₁₁N₂O₄

     empirical weight = \frac{molecular weight}{2} = \frac{374}{2} = 187u

The molecular formula is the actual combination of atoms in a compound. so the molecular formula of the compound is C₁₄H₂₂N₄O₈

learn more:

Molecular mass brainly.com/question/5546238

#learnwithBrainly

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