Answer:
4L
Explanation:
To obtain the volume of O2 at stp, first, we need to determine the number of mole of O2.
From the question given above,
Mass of O2 = 5.72g
Molar Mass of O2 = 32g/mol
Number of mole =Mass/Molar Mass
Number of mole of O2 = 5.72/32
Number of mole of O2 = 0.179 mole
Now, we can calculate the volume of O2 at stp as follow:
1 mole of a gas occupy 22.4L at stp.
Therefore, 0.179 mole of O2 will occupy = 0.179 x 22.4 = 4L
Therefore, the volume occupied by the sample of O2 is 4L
112 km is travelled by car in 60 minutes
1 km is travelled by car in 60/112 minutes
56 km is travelled by car in 60/112*56 = 30 minutes = 0.5 hours
Explanation:
Answer:
0.02moles
Explanation:
To answer this question, the general gas law equation is used. The General gas law is:
Pv = nRT
Where; P = standard atmospheric pressure (1 atm)
V = volume (L)
n = number of moles
R = Gas law constant
T = Temperature
For this question; volume = 1.00L, atmospheric pressure (P) = 1 atm, R = 0.0821 L-atm / mol K, T = 600K, n = ?
Therefore; Pv = nRT
n = PV/RT
n = 1 × 1/ 0.0821 × 600
n = 1/49.26
n = 0.0203moles
Hence, there are 0.02 moles of gas.
Calculations in chemistry can range from large numbers to the smallest number in decimals to be more accurate in data results. When this occurs using scientific notations allows you to note down results regardless of size as accurate as possible without writing a lot of numbers.
1 mole of Ethanol molecule contains an Avogadro Number of molecules
1 mole of Ethanol molecule contains 6.02 * 10²³ molecules
3.5 moles of Ethanol will then contain: 3.5 * 6.02 * 10²³
= 2.107 * 10²⁴ molecules.
