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masya89 [10]
3 years ago
9

What pressure will 14.0 g of CO exert in a 3.5 L container at 75°C

Chemistry
1 answer:
Mariana [72]3 years ago
3 0

<u>Answer:</u> The pressure of CO gas is 4.08 atm

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Given mass of CO = 14 g

Molar mass of CO = 28 g/mol

Putting values in above equation, we get:

\text{Moles of CO}=\frac{14g}{28g/mol}=0.5mol

To calculate the pressure of the gas, we use the equation given by ideal gas which follows:

PV=nRT

where,

P = pressure of the gas = ?

V = Volume of the gas = 3.5 L

T = Temperature of the gas = 75^oC=[75+273]K=348K

R = Gas constant = 0.0821\text{ L. atm }mol^{-1}K^{-1}

n = number of moles of CO gas = 0.5 moles

Putting values in above equation, we get:

P\times 3.5L=0.5mol\times 0.0821\text{ L. atm }mol^{-1}K^{-1}\times 348K\\\\P=\frac{0.5\times 0.0821\times 348}{3.5}=4.08atm

Hence, the pressure of CO gas is 4.08 atm

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