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valentina_108 [34]
3 years ago
7

What is the molarity of a solution made by dissolving 8.60 g of a solid with a

Chemistry
1 answer:
Dima020 [189]3 years ago
8 0

Answer:

1.43 M

Explanation:

We'll begin by calculating the number of mole of the solid. This can be obtained as follow:

Mass of solid = 8.60 g

Molar mass of solid = 21.50 g/mol

Mole of solid =?

Mole = mass / molar mass

Mole of solid = 8.60 / 21.50

Mole of solid = 0.4 mole

Next, we shall convert 280 mL to litre (L). This can be obtained as follow:

1000 mL = 1 L

Therefore,

280 mL = 280 mL × 1 L / 1000 mL

280 mL = 0.28 L

Thus, 280 mL is equivalent to 0.28 L.

Finally, we shall determine the molarity of the solution. This can be obtained as illustrated below:

Mole of solid = 0.4 mole

Volume = 0.28 L

Molarity =?

Molarity = mole / Volume

Molarity = 0.4 / 0.28

Molarity = 1.43 M

Thus, the molarity of the solution is 1.43 M.

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Explanation:

As it is known that non-electrolytes do not dissociate. Therefore, molarity of such a solution is equal to the osmolarity of solution.

As, molar mass of ethanol = 46.07 g/mol

Therefore, no. of moles of ethanol will be calculated as follows.

               No. of moles = \frac{mass}{\text{molar mass}}

                                     = \frac{0.00001 g}{46.07 g/mol}

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As, molarity is moles of solute in liter of solution. Hence, molarity of ethanol is as follows.

                           Molarity = \frac{\text{no. of moles}}{volume}

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                                          = 2.17 \times 10^{-7} mol/L

Since, for the given solution Molarity = osmolarity

Thus, we can conclude that osmolarity of .00001 grams (0.1 mg%) of ethanol  in 1 L is 2.17 \times 10^{-7} osmol/L.

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3 years ago
student in chemistry 150-02 weighed out 55.5g of octane c8h18 and allowed it to react with oxygen, o2 the product formed were ca
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Answer:

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Explanation:

unbalanced reaction:

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(2) 10(4H+ + O2 → 2H2O)

⇒ 40H+ + 10O2 → 20H2O

(1) + (2):

balanced reaction:

⇒ C8H8 + 10O2 → 8CO2 + 4H2O

                      8 - C - 8

                     20 - O2 - 20

                      8 - H - 8

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