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Marrrta [24]
3 years ago
5

Identify which trends in the diagrams below describe atomic radius, ionization energy, electron affinity, and electronegativity.

Chemistry
1 answer:
mihalych1998 [28]3 years ago
8 0

a)  figure describe ionization energy , electron affinity & electron negativity

b) figure describe Atomic Radius

c) does represent anything

Electronegativity : An atom attracted the bond pair of electrons in a covalent bond is called electronegativity of an element.       H-->Cl

Ionization energy : The amount of energy is required to remove of an electron from an isolated gas atom is called Ionization energy.   M + IP-----> M+ + e-

Electron affinity: The amount of enery is released when an electron added to an isolated atom is called electron affinity.

   X + e- ------> X- =- EA

Atomic radius ; The distance between the center of neuclies and outer most shell is called atomic radius.

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Answer:

Explanation:

Diamond has lesser density than platinum . So , if we take equal mass of both , the volume of mass of platinum will be far less .

The density of both diamond and platinum are  more than water so both of them will be drowned in water completely . They will not float . On being drowned , platinum will displace lesser volume of water because of its less volume . So volume change in case of platinum mass will be far less . The volume change for diamond will be more because of its bigger size.

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Which is a set of valid quantum numbers?
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The last set which is n=4 l=3 m=3 is a valid set

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Solve and show work. Li2S + 2 HNO3 --> 2 LiNO3 + H2S (a) Calculate the mass of lithium sulfide that will react with 250 mL of
Elenna [48]

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2 years ago
A solution was found to have a 15.6 % transmittance at 500 nm, its wavelength of maximum absorption, using a cell with a path le
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For the absorbance of the solution in a 1.00 cm cell at 500 nm  is mathematically given as

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<h3>What is the absorbance of the solution in a 1.00 cm cell at 500 nm?</h3>

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Generally, the equation for the Beer’s law is mathematically given as

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0.8069 = ε*c*(5.00 )

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then for when ε*c is constant

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In conclusion, the absorbance of the solution in a 1.00 cm cell at 500 nm is

A’ = 0.16138

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