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Blizzard [7]
3 years ago
7

What is the Morgan-Keenan Spectral Classification system?

Physics
1 answer:
Angelina_Jolie [31]3 years ago
4 0

Answer: A method of classifying stars by their temperatures and compositions.

Explanation:

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1. a) What is the weight of a 20.0 kg girl on earth?
ki77a [65]

Answer: weight= 196

Explanation:weight= mg

20•9.8= 196

8 0
3 years ago
What is the potential energy of a 3 kg- ball that is on the ground?
hammer [34]
With respect to the ground, the 3 kg object has no or 0 potential energy, as one can compute the potential energy as Ep = mgh. Since the object is on the ground it posses no height and thus no potential energy.
4 0
3 years ago
A cannon fires a cannonball 500.0 m downrange when set at a 45.0o angle. At what velocity does the cannonball leave the cannon?
kobusy [5.1K]

Answer:

v = 70 m/s

Explanation:

Range on the cannon ball is given as

d = 500.0 m

here the angle of the projection of the ball is given as 45 degree

now we know that if the velocity of the ball is "v" then its two components will be given as

v_x = vcos45

v_y = vsin45

so here time of flight of the motion is given as

T = \frac{2v_y}{g}

T = \frac{2vsin45}{g}

also the range is given as

R = v_x T

R = (vcos45)(\frac{2vsin45}{g})

now plug in all data in this equation

500.0 = \frac{v^2(2sin45cos45)}{g}

v = 70 m/s

4 0
3 years ago
What does the term equilibrium refer to
igor_vitrenko [27]
Equilibrium<span>-the condition of a system when no observable change is taken place or the kinetic energy is equal. </span>Equilibrium means<span> to stay balanced or equal.</span>
6 0
3 years ago
Read 2 more answers
A 4.40-m-long, 500 kg steel uniform beam extends horizontally from the point where it has been bolted to the framework of a new
icang [17]

Answer:

Torque=13798.4 N.m

Explanation:

Given data

Mass of beam m₁=500 kg

Mass of the person m₂=70 kg

length of steel r₁=4.40m

center of gravity of the beam is at r₂=r₁/2 =4.40/2 = 2.20m

To find

Torque

Solution

Torque due to beam own weight

T_{1}=m_{1}gr_{1}\\ T_{1}=500*2.2*9.8\\T_{1}=10780N.m

Torque due to person

T_{2}=m_{2}r_{2}g\\T_{2}=70*(4.40)*(9.8)\\T_{2}=3018.4 N.m

Now for total torque

T_{total}=T_{1}+T_{2}\\T_{total}=10780+3018.4\\T_{total}=13798.4N.m

4 0
3 years ago
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