Answer:
she is going to be mad dude
Answer:
66.375 x 10⁻⁶ C/m
Explanation:
Using Gauss's law which states that the net electric flux (∅) through a closed surface is the ratio of the enclosed charge (Q) to the permittivity (ε₀) of the medium. This can be represented as
;
∅ = Q / ε₀ -----------------(i)
Where;
∅ = 7.5 x 10⁵ Nm²/C
ε₀ = permittivity of free space (which is air, since it is enclosed in a bag) = 8.85 x 10⁻¹² Nm²/C²
Now, let's first get the charge (Q) by substituting the values above into equation (i) as follows;
7.5 x 10⁵ = Q / (8.85 x 10⁻¹²)
Solve for Q;
Q = 7.5 x 10⁵ x 8.85 x 10⁻¹²
Q = 66.375 x 10⁻⁷ C
Now, we can find the linear charge density (L) which is the ratio of the charge(Q) to the length (l) of the rod. i.e
L = Q / l ----------------------(ii)
Where;
Q = 66.375 x 10⁻⁷ C
l = length of the rod = 10.0cm = 0.1m
Substitute these values into equation (ii) as follows;
L = 66.375 x 10⁻⁷C / 0.1m
L = 66.375 x 10⁻⁶ C/m
Therefore, the linear charge density (charge per unit length) on the rod is 66.375 x 10⁻⁶ C/m.
Explanation:
It is given that,
= -40 mi/h, = -40 mi/h
The negative sign indicates that x and y are decreasing.
We have to find 
. Equation for the given variables according to the Pythagoras theorem is as follows.
Now, we will differentiate each side w.r.t 't' as follows.
or, 
So, when x = 4 mi, and y = 3 mi then z = 5 mi.
As,
= 
= 
= 52
Thus, we can conclude that the cars are approaching at a rate of 52 mi/h.
Answer: The molar heat capacity of aluminum is 
Explanation:
As we know that,
![m_1\times c_1\times (T_{final}-T_1)=-[m_2\times c_2\times (T_{final}-T_2)]](https://tex.z-dn.net/?f=m_1%5Ctimes%20c_1%5Ctimes%20%28T_%7Bfinal%7D-T_1%29%3D-%5Bm_2%5Ctimes%20c_2%5Ctimes%20%28T_%7Bfinal%7D-T_2%29%5D)
.................(1)
where,
q = heat absorbed or released
= mass of water = 130.0 g
= mass of aluminiunm = 23.5 g
= final temperature
= 
= temperature of water = 
= temperature of aluminium = 
= specific heat of water= 
= specific heat of aluminium= ?
Now put all the given values in equation (1), we get
![130.0\times 4.184\times (299-296)=-[23.5\times c_2\times (299-373)]](https://tex.z-dn.net/?f=130.0%5Ctimes%204.184%5Ctimes%20%28299-296%29%3D-%5B23.5%5Ctimes%20c_2%5Ctimes%20%28299-373%29%5D)
Molar mass of Aluminium = 27 g/mol
Thus molar heat capacity =
