Answer:
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The work done by a 10 HP motor when it raises a 1000 Newton weight at a vertical distance of 5 meters is <u>5kJ</u>.
Define work. Explain the rate of doing work.
Work is <u>the energy that is moved to or from an item by applying force along a displacement</u> in physics. For a constant force acting in the same direction as the motion, work is <u>easiest expressed as the product of </u><u>force </u><u>magnitude and distance traveled</u>.
Since the <u>force </u><u>transfers one unit of energy for every unit of </u><u>work </u><u>it performs</u>, the rate at which work is done and energy is used are equal.
Solution Explained:
Given,
Weight = 1000N and distance = 5m
A/Q, the work here is done in lifting then
Work = (weight) × (distance moved)
= 1000 X 5
= 5000Nm or 5000J = 5kJ
Therefore, the work done in lifting a 1000 Newton weight at a vertical distance of 5 meters is 5kJ.
To learn more about work, use the link given
brainly.com/question/25573309
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Answer:
(absolute).
Explanation:
Given that
Pressure ratio r
r=8
-----1
P₁(gauge) = 5.5 psig
We know that
Absolute pressure = Atmospheric pressure + Gauge pressure
Given that
Atmospheric pressure = 14.5 lbf/in²
P₁(abs) = 14.5 + 5.5 psia
P₁(abs) =20 psia
Now by putting the values in the above equation 1
Therefore the exit gas pressure will be 160 psia (absolute).
