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Igoryamba
3 years ago
12

In a nuclear power plant, Choose one: A. control rods regulate the rate of the reaction by releasing excess neutrons. B. pitchbl

ende (U238) is the most common fuel. C. there must be enough nuclear fuel to exceed a critical mass. D. fusion is happening.
Physics
1 answer:
Veronika [31]3 years ago
5 0

Answer:

option A.

Explanation:

The correct answer is option A.

Nuclear power plant are used to generate electricity. In these power plant energy is produced by fission in the nuclear reactor.

The most common fuel used for the production of energy is U-235.

Control rods are inserted in the reactor if energy requirement is less and when energy requirement is large Control rods are remove. Hence, we can say that control rod can be used to regulate the reaction in the nuclear power plant.

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Emily is a competitive swimmer. Why does wearing a swim cap help Emily swim faster?
sladkih [1.3K]

Answer:

It's helps Emily became when she swims her hair is not in the way creating friction and making her swim faster. friction acts between two metals blocks that slide past each other.

Explanation:

6 0
3 years ago
What are the disadvantages of using alcohol instead of mercury in a thermometer ?​
vichka [17]

Answer:

alcohol thermometers are used rather than Mercury thermometers in very cold regions because alcohol has a lower freezing point than Mercury.

Explanation:

6 0
3 years ago
the net force on a vehicle is accelerating at a rate of 1.5 milliseconds is 1800 Newtons. What is the mass of the vehicles neare
Goryan [66]

Answer:

The mass is 1200 kilograms

Explanation:

Because Force is equal to mass times acceleration (F=m×a)

F=m×a

1800N=?×1.5

1800÷1.5=1200

1800N=1200Kg×1.5

7 0
3 years ago
a 0.0780 kg lemming runs off a 5.36 m high cliff at 4.84 m/s. what is its kinetic energy when it's 2.00 m above the ground
Blababa [14]

Answer:

KE_2 = 3.48J

Explanation:

Conservation of Energy

E_1 = E_2

PE_1+KE_1 = PE_2+KE_2

m*g*h+(1/2)m*v² = m*g*h+(1/2)m*v²

(0.0780kg)*(9.81m/s²)*(5.36m)+(.5)*(0.0780kg)*(4.84m/s)² = (0.0780kg)*(9.81m/s²)*(2m)+KE_2

4.10J+0.914J = 1.53J + KE_2

5.01J = 1.53J + KE_2

KE_2 = 3.48J

3 0
3 years ago
A girl is sitting in a sled sliding horizontally along some snow (there is friction present).
Over [174]

Answer:

159 N

Explanation:

The force of friction, Fr is a product of coefficient of feiction and the normal force. Therefore, Fr=uN where N is the normal force and u is coefficient of friction. Here, we have two coefficients of friction but since it is sliding, then we use coefficient of kinetic energy. Substituting 0.25 for u and 636 N for N then

Fr=0.25*636=159 N

Therefore, the force of friction is equivalent to 159 N

4 0
3 years ago
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