Small quantities of oxygen can be prepared in the laboratory by heating potassium chlorate, KClO3(s).
1 answer:
Answer:
26.110 grams of O2 produced.
Explanation:
Calculate the amount of moles in KClO3 by dividing the amount of grams given by the atomic weight of the substance.
To get the atomic weight: K = 39.098, Cl = 35.45, O = 15.999, and there are 3 molecules of Oxygen, so multiply 15.999 by three.
39.098 + 35.45 + (15.999 * 3) = 122.548.
66.7g / 122.548 atomic mass = 0.544 moles.
The ratio of moles of KClO3 to moles of O2 is 2 to 3.
=
Cross multiply to get 1.632 = 2y. Y = 0.816, meaning 0.816 moles of O2 will be produced.
Convert this into grams by multiplying by the atomic weight of O2 (15.999 * 2 = 31.998).
0.816 * 31.998 = 26.110 grams of O2 produced.
You might be interested in
The pH of the solutions is 12.67.
<h3>What is pH of a Solution?</h3>
pH is the measurement of how acidic or basic a solution is. The range of pH values is from 0 to 14. Lower pH values mean higher acidity, while higher pH means higher basicity. If the pH value is equal to 7, then the solution is neutral.
To calculate the pH of the solution, a few approaches are possible. Here, the pOH of the solution is calculated first using the molar concentration of ions. Because pH + pOH = 14, the pH of the solution can then be calculated by subtracting pOH from 14.
Because 2 moles of ions are formed per mole of
dissolved, the pOH of a saturated
solution at
is,
Concentration () of
ions,
= 0.02335 mol
/L X 2 mol
/1 mol
= 0.0467 mol
/L
*pOH of saturated solution,
pOH = -log []
pOH = -log [0.0467 mol /L ]
pOH = 1.33
*pH of saturated solution,
pH = 14 - 1.33
pH = 12.67
Hence, the pH of the solutions is 12.67.
Learn more about pH of the solutions here:
#SPJ4