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kolbaska11 [484]
3 years ago
8

A 60 kg man is sitting on the floor of an airplane 8000 m high traveling at 850 km/hr. How much total mechanical energy does he

have relative to the reference frame of the plane?
Physics
1 answer:
Alik [6]3 years ago
6 0

Relative to reference frame of the airplane he's sitting in:

-- Gravitational potential energy = (mass) (gravity) (height)

His height above the airplane is zero, so his GPE is zero.

-- Kinetic energy = (1/2) (mass) (speed)²

His speed relative to the airplane is zero, so his KE is zero.

Mechanical energy = (potential energy) + (kinetic energy)

Mechanical energy = ( 0 ) + ( 0 )

The poor fellow's total mechanical energy is <em>zero</em><em> </em>.

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The elapsed time when the particle returns to the origin is determined from the ratio of initial velocity and acceleration of the particle.

<h3>Time of motion of the particle</h3>

The time of motion of the particle is calculated by applying Newton's second law of motion.

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2 years ago
A 2.0-cm-diameter parallel-plate capacitor with a spacing of 0.50 mm is charged to 200 V?What is the total energy stores in the
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1) 1.11\cdot 10^{-7} J

The capacitance of a parallel-plate capacitor is given by:

C=\frac{\epsilon_0 A}{d}

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\epsilon_0 is the vacuum permittivity

A is the area of each plate

d is the distance between the plates

Here, the radius of each plate is

r=\frac{2.0 cm}{2}=1.0 cm=0.01 m

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A=\pi r^2 = \pi (0.01 m)^2=3.14\cdot 10^{-4} m^2

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C=\frac{(8.85\cdot 10^{-12} F/m)(3.14\cdot 10^{-4} m^2)}{5\cdot 10^{-4} m}=5.56\cdot 10^{-12} F

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and using

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u=\frac{1}{2}(8.85\cdot 10^{-12} F/m)(4\cdot 10^5 V/m)^2=0.71 J/m^3

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