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Triss [41]
2 years ago
10

What is the speed of an object traveling a distance of 25 meters in 25 seconds

Physics
2 answers:
tiny-mole [99]2 years ago
7 0

Answer: 2.23694 miles per hour

Explanation:

sergeinik [125]2 years ago
6 0

Answer:

1 meter per second

Explanation:

Speed=Distance/Time

S=D/T

S=25/25

S=1

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Because plate movements have raised ancient sea floors above sea level,
Elena-2011 [213]
Because plate movements have raised ancient sea floors above sea level, _________?

<span>Answer : Limestone that began as coral reefs can be found on the continents.</span>

3 0
2 years ago
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A differnece in electric potential is required for an electric charge to flow through a wire.
cupoosta [38]

Answer:

TRUE

Explanation:

6 0
2 years ago
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Which of the following is not sublimable? *
galina1969 [7]

Answer:

where is your option ?

you can't write option so I think

sodium chloride is not sublimable

7 0
3 years ago
The diver on the diving board is 10 meters high and has a mass of 0.050kg, what is his GPE?
sveta [45]

Answer:

<h2>4.9 J</h2>

Explanation:

The gravitational potential energy of a body can be found by using the formula

GPE = mgh

where

m is the mass

h is the height

g is the acceleration due to gravity which is 9.8 m/s²

From the question we have

GPE = 10 × 9.8 × 0.05

We have the final answer as

<h3>4.9 J</h3>

Hope this helps you

6 0
3 years ago
Un puente de acero de 100 m de largo a 8° C aumenta su temperatura a 24°C ¿Cuánto medirá su longitud? Valor del coeficiente de d
BartSMP [9]

La longitud <em>final</em> del puente de acero es 100.018 metros.

Asumamos que la dilatación <em>térmica</em> experimentada por el puente de acero es <em>pequeña</em>, de modo que podemos emplear la siguiente aproximación <em>lineal</em> para determinar la longitud <em>final</em> del puente de acero (L), en metros:

L = L_{o}\cdot [1+\alpha\cdot (T_{f}-T_{o})] (1)

Donde:

  • L_{o} - Longitud inicial del puente, en metros.
  • \alpha - Coeficiente de dilatación, sin unidad.
  • T_{o} - Temperatura inicial, en grados Celsius.
  • T_{f} - Temperatura final, en grados Celsius.

Si tenemos que L_{o} = 100\,m, \alpha = 11.5\times 10^{-6}, T_{o} = 8\,^{\circ}C y T_{f} = 24\,^{\circ}C, entonces la longitud final del puente de acero es:

L = (100\,m)\cdot [1+(11.5\times 10^{-6})\cdot (24\,^{\circ}C - 8\,^{\circ}C)]

L = 100.018\,m

La longitud <em>final</em> del puente de acero es 100.018 metros.

Para aprender más sobre dilatación térmica, invitamos cordialmente a ver esta pregunta verificada: brainly.com/question/24953416

5 0
2 years ago
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