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jolli1 [7]
3 years ago
9

Which is a substance that takes the shape and volume of its container?

Physics
1 answer:
Gnom [1K]3 years ago
7 0
Which is a substance that takes the shape and volume of its container?

liquid

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Which two surfaces would have the lowest coefficient of friction?
arsen [322]

Answer: Ice on ice

Explanation:

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3 years ago
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The red light from the ant passed into the lens
s344n2d4d5 [400]

<u>Answer:</u>

<em>When red light enters the lens its wavelength decreases but its frequency remains the same. </em>

<u>Explanation:</u>

Lens is made of glass which is a <em>denser medium</em> when compared with air. Thus light will undergo refraction and bend toward the normal. On entering  a denser medium from rarer medium the speed of light decreases.

<em>Speed, frequency and wavelength of an electromagnetic wave</em> are related according to the equation.

<em>                                                                 v=ϑλ </em>

Where is <em>v is the frequency,  λ is the wavelength and v is the speed of the em wave. </em>

On entering the lens the wavelength of the red light as well as speed decreases but the<em> frequency remains the same. </em>

6 0
3 years ago
Finding the area of a trapezoid on a velocity versus time graph will tell you
julsineya [31]
The answer is c. velocity
6 0
3 years ago
A sound wave takes 0.2 seconds to travel 306 meters.
chubhunter [2.5K]

Answer:

1530 m/s

Explanation:

Given that :

Speed = distance / time

Travel time take = 0.2 s

Distance covered = 306 metres

The speed of sound in the material :

Speed = distance / time = 306 m / 0.2

Speed = 1530 m/s

6 0
3 years ago
his is a multi-part question. Once an answer is submitted, you will be unable to return to this part. Air enters a nozzle steadi
zepelin [54]

Answer:

his is a multi-part question. Once an answer is submitted, you will be unable to return to this part. Air enters a nozzle steadily at 2.21 kg/m3 and 40 m/s and leaves at 0.762 kg/m3 and 192 m/s. The inlet area of the nozzle is 90 cm2.

determine (a) the mass flow rate through the nozzle, and (b) the exit area of the nozzle.

a)0.7956kg/s

b)5.437 × 10⁻³m²

Explanation:

The concepts related to the change of mass flow for both entry and exit is applied

The general formula is defined by

\dot{m}=\rho A V

Where,

\dot{m} = mass flow rate\\\rho = Density\\V = Velocity

values are divided by inlet(1) and outlet(2) by

\rho_1 = 2.21kg/m^3V_1 = 40m/s

A_1 = 90*10^{-4}m^2\\\rho_2 = 0.762kg/m^3\\V_2 = 192m/s

PART A) Applying the flow equation

\dot{m} = \rho_1 A_1 V_1\\\dot{m} = (2.21)(90*10^{-4})(40)\\\dot{m} = 0.7956kg/s

PART B) For the exit area we need to arrange the equation in function of Area, that is

A_2 = \frac{\dot{m}}{\rho_2 V_2}\\A_2 = \frac{0.7956}{(0.762)(192)}\\A_2 = 5.437*10^{-3}m^2

7 0
3 years ago
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