Answer:
Acceleration of Sea Lion is 4.41 g
This is 49% of maximum jet acceleration given as a = 9g
Explanation:
As we know that the radius of the circular loop is given as
R = 0.37 m
The speed of the fish is given as
![v = 4 m/s](https://tex.z-dn.net/?f=v%20%3D%204%20m%2Fs)
Now the centripetal acceleration of the sea lion is given as
![a_c = \frac{v^2}{R}](https://tex.z-dn.net/?f=a_c%20%3D%20%5Cfrac%7Bv%5E2%7D%7BR%7D)
![a_c = \frac{4^2}{0.37}](https://tex.z-dn.net/?f=a_c%20%3D%20%5Cfrac%7B4%5E2%7D%7B0.37%7D)
![a_c = 43.2 m/s^2](https://tex.z-dn.net/?f=a_c%20%3D%2043.2%20m%2Fs%5E2)
as we know that
![g = 9.8 m/s^2](https://tex.z-dn.net/?f=g%20%3D%209.8%20m%2Fs%5E2)
so we have
![a = 4.41 g](https://tex.z-dn.net/?f=a%20%3D%204.41%20g)
Now Percentage of this acceleration wrt maximum jet acceleration is given as
![P = \frac{4.41 g}{9g} \times 100](https://tex.z-dn.net/?f=P%20%3D%20%5Cfrac%7B4.41%20g%7D%7B9g%7D%20%5Ctimes%20100)
%
Answer:
Mass and velocity.
Explanation:
Kinetic energy <u>is the energy that an object has due to its movement</u>, mathematically it is represented as follows:
![K=\frac{1}{2} mv^2](https://tex.z-dn.net/?f=K%3D%5Cfrac%7B1%7D%7B2%7D%20mv%5E2)
where
is the mass of the object, and
is its velocity at a given point in time.
So we can see that to find the kinetic energy just before the ball hits the gound, we need the quantities:
- mass of the ball
- velocity of the ball before it hits the ground
With the knowledge of these two quantities the kinetic energy of the ball before touching the gound can be determined.
Yes, this is correct Answer.
I think the correct answer would be that there are a relatively small number of moles of HCl present. Dilute would mean that there are very few solute particles dissolved as compared to the solvent particles in the solution. Hope this helps.