Answer:
a) The equation for ball´s velocity is V₁ = (F*t)/m
b) The ball velocity after collision is 7.87 m/s
c) The heigh from which the ball is dropped is 3.16 m
Explanation:
Given data:
m = mass of golf ball = 0.19 kg
t = interaction time = 0.13 s
F = force = 11.5 N
a) Due the collision is eslastic, the change of momentum is:
ΔV*m = F*t
V₁ - V₀ = (F*t)/m
V₁ = ((F*t)/m) + V₀
Where V₀ = 0
V₁ = (F*t)/m
b) Replacing:
c) According conservation of kinetic energy:
(Ek - Ep)initial = (Ek - Ep)final
0 + mgh = (1/2)mV₁² + 0
Clearing h:
10 grams of salt is the result
When the number of electrons striking the anode of an x-ray tube is increased, the <u>density</u> of emitted X-Rays increases.
Option: 1
<u>Explanation:</u>
As the electron speed increases, the heat radiation also increases from thermionic emission, which causes more heat and more X-ray release. X-rays are produced by an a vacuum tube called X-ray tube that uses more voltage to make the electrons accelerate which the hot cathode releases to a high velocity.
This high speed electrons meets in a collision with a metal target which is the anode, and thus create the X-rays. So, the electron number available and the time period set for their release from the filament determines how many x-rays are produced from the anode. Hence, more the number of electrons striking the anode,the more is the emission of x-rays.
<span>The equation for momentum is p = mv, where m is the mass of the object and v is its velocity. Through conservation of momentum, we know that the momentum of the rifle must be of the same magnitude and opposite direction to that of the bullet. Thus we can form two expressions for the respective momenta, set them equal, and solve for the recoil speed of the rifle.
718*0.0159 = vr*5.05 where vr is the rifle recoil speed.
Solving for vr = 718*0.0159/5.05 = 2.26 meters/second.</span>
The radial force on the particle is given by the Lorentz force. They don't give you the velocity so you have to solve for it in terms of the radius and get them to cancel.