Question

The net fedrce on a 12 kg cart is 3.2N backward. Ignoring friction, what is the acceleration

Answer 1

We have,

Mass,m = 12 kg

Force,F = 3.2 N

To be calculated:-

Calculate the acceleration ( a ) .

Solution:-

We know that,

$\bf \: Force = Mass × Acceleration$

$\sf\implies \: 3.2 = 12 \: \times a$

$\sf \implies \: a = \dfrac{3.2}{12}$

$\sf \implies \: a = \dfrac{32}{12 \times 10}$

$\sf \implies \: a \: = \dfrac{8}{3 0}$

$\sf \implies \: a = 0.266$

$\sf \implies \: a = 0.27 \: m {s}^{ - 2} \: (approx)$

Answer 2

We are given with the amount of force applied and mass of a cart and we have to find the acceleration of the box.

• Force applied = 3.2 N
• Mass of the cart = 12 kg

According to Netwon's 2nd law,

After deriving, we will get that

• Force = Mass × Accleration

Plugging the given values to get mass,

➝ 3.2 N = 12 kg × accleration

➝ Accleration = 3.2 / 12 m/s²

➝ Accleration = 0.27 m/s² (approx.)

Thus, the required answer is Option A.

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