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kiruha [24]
3 years ago
7

A stone is thrown vertically upwards with an initial velocity of 40 ms-1. Find the maximum height reached by the stone. What is

the net displacement and the total distance covered by the stone?
Physics
1 answer:
Lyrx [107]3 years ago
8 0
To find the maximum height we use the expression:
U²=2gh
Where u is the initial velocity,
g is gravitational field strength
h is the maximum height.
h=u²/2g
h=40²/20
=1600/20
=80m
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