The magnitude of the force required to stop the weight in 0.333 seconds is 67.6 N.
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Magnitude of required force to stop the weight</h3>
The magnitude of the force required to stop the weight in 0.333 seconds is calculated by applying Newton's second law of motion as shown below;
F = ma
F = m(v/t)
F = (mv)/t
F = (5 x 4.5)/0.333
F = 67.6 N
Thus, the magnitude of the force required to stop the weight in 0.333 seconds is 67.6 N.
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Answer:

Explanation:
Given that
V= 12 V
K=3
d= 2 mm
Area=5.00 $ 10#3 m2
Assume that
$ = Multiple sign
# = Negative sign

We Capacitance given as
For air







Net capacitance
C=C₁+C₂

We know that charge Q given as
Q= C V


Explanation:
Significant figures of a number written in positional notation are digits that carry meaningful contributions to the measurement resolution of the number.
The length should be 450 cm
and tooth length should be 0.45 cm i believe
hope i was able to help out!!! :)
Explanation:
The density of an object can be calculated using the formula as follows :

Here,
m is mass of the object and V is its volume
The mass of an object can b measured in grams and its volume in cubic cm. So, the density of object is measured in g/cm³. Hence, out of given options the possible value of density of an object is 6 g/cm³.