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zhuklara [117]
3 years ago
10

A soccer ball is kicked with a speed of 35 m/s at an angle of 30° with respect to the ground and lands a certain distance away f

rom the point it was kicked. If a second ball were kicked from the same place with a speed of 37 m/s, at what angle with respect to the ground could its initial velocity be such that it lands in the same place as the first ball?
Physics
1 answer:
NNADVOKAT [17]3 years ago
7 0

Answer:

θ = 25.4º

Explanation:

For this exercise we can use the projectile launch equations, let's use the scope ratio

      R = vo² sin 2θ / g

For the first ball

     R1 = 35² 2 sin (2 30) /9.8

     R1 = 108.25 m

For the second ball,  they ask that the second ball fall in the same place, so the horizontal distance is the same

    R2 = R1

Therefore we calculate the angle

    sin 2θ = R1 g / vo²

    sin 2θ = 108.25 9.8 / 37²

    sin 2θ = 0.7749

    2θ = sin⁻¹ (0.7749)

    2θ = 50.8º

    θ = 25.4º

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<h2>Answer:</h2>

(a) standard deviation = σ = 4.9996

(b) variance = σ² = 24.996

<h2>Explanation:</h2><h2 />

<em>Given frequency table (find attached as Table 1);</em>

<u></u>

(a) To find the sample standard deviation and sample variance, follow these steps;

<em>i. Calculate the mid-point c for each group by using the mid-point formula;</em>

c = (lower bound + upper bound) / 2

=> c = (6.51 + 8.50) / 2 = 7.505

=> c = (8.51 + 10.50) / 2 = 9.505

=> c = (10.51 + 12.50) / 2 = 11.505

=> c = (12.51 + 14.50) / 2 = 13.505

=> c = (14.51 + 16.50) / 2 = 15.505

<em>So the new table becomes (find attached as Table 2);</em>

<em>ii. Calculate the total number of samples (n) which is the sum of all the frequencies.</em>

n = 50+18+42+20+46

n = 176

<em>iii. Calculate the mean (M)</em>

This is done by first multiplying the midpoints by the corresponding frequencies and then dividing the result by the total number of samples (n).

M = [(7.505 x 50) + (9.505 x 18) + (11.505 x 42) + (13.505 x 20) + (15.505 x 46)] / 176

M = [375.25 + 171.09 + 483.21 + 270.1 + 713.23] / 176

M = [2012.88] / 176

M = 11.44

<em>iv. Find the variance (σ²);</em>

The variance is calculated using the following formula

σ² = [Σ(f x c²) - (n x M²)] / (n - 1)                ------------(i)

Where;

f = frequency of each boundary data point

<em>=>  Let's first calculate </em>Σ(f x c²).

This is done by finding the sum of the product of the frequency (f) of each boundary point and the square of their corresponding mid-points(c)

Σ(f x c²) = [(50 x 7.505²) + (18 x 9.505²) + (42 x 11.505²) + (20 x 13.505²) + (46 x 15.505²)]

Σ(f x c²) = [(2816.25125) + (1626.21045) + (5559.33105) + (3647.7005) + (11058.63115)]

Σ(f x c²) = 24708.1244

<em>=> Now calculate (n x M²)</em>

n x M² = 176 x 11.44²

n x M² = 23033.7536

<em>=> Now substitute these values into equation (i) to calculate the variance</em>

σ² = [Σ(f x c²) - (n x M²)] / (n - 1)

σ² = [24708.1244 - 23033.7536] / (176 - 1)

σ² = [4374.3708] / (175)

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Therefore, the variance is 24.996

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The standard deviation is the square root of the variance. i.e

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σ = √24.996

σ = 4.9996

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By conservation of energy, the kinetic energy has to equal the change in potential energy, so KE=q*V. The energy of the electron in electron-volts is numerically the same as the voltage between the plates.

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To learn more about  kinetic energy in electric field  here

brainly.com/question/8666051

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Answer:

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