Answer:
<h2>Because water can lose and accept H + ions .......</h2>
Heat used by electric heater :
Q = m • c • ∆T
Q = (75 kg)(4200 J/kg°C)(43°C - 15°C)
Q = 8.82 × 10⁶ J
Cost of electrical energy :
Cost = (8.82 × 10⁶ J)/(3.6 × 10⁶ J) • ($ 0.15)
Cost = $ 0.3675
The distance from the sun to Neptune is about the same as the distance from Neptune to the next closest star, Proxima Centauri