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Nikolay [14]
4 years ago
12

Why do moon phases repeat about every 28 days

Physics
1 answer:
svet-max [94.6K]4 years ago
8 0

Moon phases repeat every 29.531 days, because as the moon revolves around the Earth, the amount of the moon's lighted half that we can see changes steadily.

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The diagram below shows different weights on the see-saw. Will the see-saw move?
oee [108]

Answer:

yes it will

Explanation:

8 0
3 years ago
The temperature of a black body is 500 and its radiation is of wavelength 600 . If the number of oscillators with energy is 100
stiks02 [169]

Answer: An equation is missing in your question below is the missing equation

a) ≈ 8396

b) 150 nm/k

Explanation:

<u>A) Determine the number of Oscillators in the black body</u>

number of oscillators = 8395

attached below is the detailed solution

<u>b) determine the peak wavelength of the black body </u>

Black body temperature = 20,000 K

applying Wien's law / formula

λmax = b / T  ------ ( 1 )

T = 20,000 K

b = 3 * 10^6 nm

∴  λmax = 150 nm/k

4 0
3 years ago
An aircraft has a mass of 3.30 x 105 kg. At a certain instant during its landing, its speed is 45.2 m/s. If the braking force is
melamori03 [73]
Ultraconservative the future and I have been working with the following questions.
8 0
4 years ago
A shopper pushes a grocery cart 20.0 m at constant speed on level ground, against a 35.0 n frictional force. he pushes in a dire
alexandr1967 [171]

Work is calculated as the product of Force, Distance, and angular motion. In this case, the work done by gravity is perpendicular to the motion of the cart, so θ = 90°

 and W=Fdcosθ

W=35.0 N x 20.0 m x cos90

W=0 J

This means that work done perpendicular to the direction of the motion is always zero.

5 0
3 years ago
One mole of an ideal gas does 3000 J of work on its surroundings as it expands isothermally to a final pressure of 1.00 atm and
taurus [48]

Answer:

(a) Initial volume will be 7.62 L

(b) Final temperature will be 303.85 K

Explanation:

We have given one mole of ideal gas done 3000 J

So work done W = 3000 J

Let initial volume is V_1 and initial pressure P_1=1atm ( As pressure is constant )

Final volume V_2=25L = 0.025 m^3

Number of moles n = 1

(B) From ideal gas of equation we know that PV=nRT

So 1.01\times 10^5\times0.025=1\times 8.31\times T

T = 303.85 Kelvin

(B) For isothermal process work done is equal to

W=nRTln\frac{V_2}{V_1}

3000=1\times 8.314\times 303.85\times ln\frac{0.025}{V_1}

ln\frac{0.025}{V_1}=1.1881

\frac{0.025}{V_1}=3.2808

V_2=0.00846m^3=7.62L

So initial volume will be 7.62 L

5 0
3 years ago
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