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4 years ago

Ejdjsjdjskskdkdkdkdkdkdkdkdkdkdkdkdjdjdjdjdjdjdjdjd

Physics

2 answers:

Inga [223]4 years ago

6 0

Answer:Ejdjsjdjskskdkdkdkdkdkdkdkdkdkdkdkdjdjdjdjdjdjdjdjd!

Explanation:

riadik2000 [5.3K]4 years ago

5 0

DOEOUEPUROYEOYEKYDKDLYDYLDULDULDULDLUDULDLYDLUDLUDLUDLUDLUDULSOYDYODYODOYXYL I LUV MY DADDY MY SUPER HIRRO

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When a 58g tennis ball is served, it accelerates from rest to a constant speed of 36 m/s. The impact with the racket gives the b

inysia [295]

We first calculate the acceleration on the ball using:
2as = v² - u²; u = 0 because ball is initially at rest
a = (36)²/(2 x 0.35)
a = 1850 m/s²
F = ma
F = 0.058 x 1850
= 107.3 Newtons

5 0

3 years ago

What voltage produces a current of 50 amps with a resistance of 20 ohms?

PIT_PIT [208]

Answer:

1000 V

Explanation:

Ohm's law:

V = IR

V = (50 A) (20 Ω)

V = 1000 V

5 0

3 years ago

The surface of the dock is 6 feet above the water. If you pull the rope in at a rate of 2 ft/sec, how quickly is the boat approa

Oduvanchick [21]

Answer:

The boat is approaching the dock at a rate of 2.5 ft/s.

Explanation:

Let the rope length be 'l' at any time 't', the distance of boat from dock be 'b' at any time 't'.

Given:

The height of dock above water (h) = 6 feet

Rate of pull of rope or rate of change of rope is, $\frac{dl}{dt}=2\ ft/s$

As clear from the question, the height is fixed and only the length 'l' and distance 'b' varies with time 't'.

Now, the above situation represents a right angled triangle as shown below.

Using Pythagoras Theorem, we have:

$l^2=h^2+b^2\\\\l^2=6^2+b^2\\\\l^2=36+b^2----------(1)$

Now, differentiating the above equation with time 't', we get:

$2l\frac{dl}{dt}=0+2b\frac{db}{dt}\\\\l\frac{dl}{dt}=b\frac{db}{dt}\\\\\frac{db}{dt}=\frac{l}{b}\frac{dl}{dt}------(2)$

Now, the distance 'b' can be calculated using 'l=10 ft' in equation (1). This gives,

$b^2=10^2-36\\\\b=\sqrt{64}=8\ ft$

Now, substituting all the given values in equation (2) and solve for $\frac{db}{dt}$ . This gives,

$\frac{db}{dt}=\frac{10}{8}\times 2\\\\\frac{db}{dt}=2.5\ ft/s$

Therefore, the boat is approaching the dock at a rate of 2.5 ft/s.

7 0

3 years ago

A vector has an x-component of 19.5m and a y-component of 28.4m. Find the magnitude and direction of the vector

Zanzabum

Answer:

34.5 m at 55.5 degrees above the positive x-axis

Explanation:

Resolving a vector means finding its components along two perpendicular axis: most commonly, they are chosen as the x and y axis.

In this problem, we have a vector whose components are:

x -component: 19.5 m

y- component: 28.4 m

The two components are perpendicular to each other: this means that we can find the magnitude of the vector by using the Pythagorean theorem

$v=\sqrt{v_x^2+v_y^2}=\sqrt{19.5^2+28.4^2}=34.5 m$

The direction, instead, can be found by using the following formula:

$\theta=tan^{-1}(\frac{v_y}{v_x})=tan^{-1} (\frac{28.4}{19.5})=55.5^{\circ}$

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3 years ago

Which would show an example of how physical changes are reversible?

laiz [17]

Examples of reversible changes include melting chocolate and changing it back into a solid by cooling it, and melting candle wax by heating it and solidifying the wax by cooling it. Reversible changes are changes that can be reversed. They are also known as physical changes.

3 0

3 years ago

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