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2 years ago

11

Liquid alcohol will change to vapor when its temperature reaches the

1 answer:

Nina [5.8K]2 years ago

4 0

C. boiling point
boiling point is the temperature at which all liquids change from liquid to gas

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Joe bought a roll of gray duct tape containing 5400 inches. If there are 5280 feet in a mile, how

miss Akunina [59]

Answer:

STANDARD: 0.085 mi, 450 ft, or 150 yds

METRIC: 0.137 km, 137.16 m, or 13716 cm

Explanation:

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3 years ago

What is a small-ball shaped organelle that helps the cell break down nutrients and old cell parts.

Gemiola [76]

Lysosome: only ones that break down old cell parts<span>
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2 years ago

Question: If red dye is added to cold water and blue dye is added to warm water, which dye will

vlada-n [284]

Answer:

Blue dye spreads out quicker

Explanation:

This is because the dye gets spread out by water molecules. Warm water has faster moving water molecules than cold water.

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3 years ago

Read 2 more answers

If ine mole of pennies were divided amung 250 million peoplein

Airida [17]

Answer:

$2.4088\times 10^{13}$ dollars each person will receive.

Explanation:

Number of people in which 1 mole of pennies is distributed = 250 million =

$1 million = 10^6$

250 million = $2.5\times 10^8$ persons

Number of pennies in 1 mole = $6.022\times 10^{23}$

Pennies per person:

$\frac{6.022\times 10^{23} pennies}{2.5\times 10^8 persons}=2.4088\times 10^{15} pennies/person$

1 penny = 0.01 $

$2.4088\times 10^{15} pennies/person=2.4088\times 10^{15}\times 0.01 \$/person=2.4088\times 10^{13} \$/person$

$2.4088\times 10^{13}$ dollars each person will receive.

7 0

3 years ago

30cm^3 of a dilute solution of Ca(OH)2 required 11 cm^3 of 0.06 mol/dm^. Hcl for complete neutralization. Calculate the concentr

Alenkasestr [34]

Answer: Thus concentration of $Ca(OH)_2$ in $mol/dm^3$ is 0.011 and in $g/dm^3$ is 0.814

Explanation:

To calculate the concentration of $Ca(OH)_2$ , we use the equation given by neutralization reaction:

$n_1M_1V_1=n_2M_2V_2$

where,

$n_1,M_1\text{ and }V_1$ are the n-factor, molarity and volume of acid which is $HCl$

$n_2,M_2\text{ and }V_2$ are the n-factor, molarity and volume of base which is $Ca(OH)_2$

We are given:

$n_1=1\\M_1=0.06mol/dm^3\\V_1=11cm^3=0.011dm^3\\n_2=2\\M_2=?\\V_2=30cm^3=0.030dm^3$ $1cm^3=0.001dm^3$

Putting values in above equation, we get:

$1\times 0.06mol/dm^3\times 0.011dm^3=2\times M_2\times 0.030dm^3\\\\M_2=0.011mol/dm^3$

The concentration in $g/dm^3$ is $0.011mol/dm^3\times 74g/mol=0.814g/dm^3$

Thus concentration of $Ca(OH)_2$ is $0.011mol/dm^3$ and $0.814g/dm^3$

4 0

3 years ago