In order for an object or a projectile to leave Earth's gravitational pull, it must reach Earth's escape velocity, meaning reach a speed of 7 miles per second (~11 km per second).
Answer:
Maximum speed ( v ) = 10.4 m/s (Approx)
Explanation:
Given:
Amplitude A = 15.0 cm = 0.15 m
Frequency f = 11.0 cycles/s (Hz)
Find:
Maximum speed ( v )
Computation:
Angular frequency = 2πf
Angular frequency = 2π(11)
Angular frequency = 69.14
Maximum speed ( v ) = WA
Maximum speed ( v ) = 69.14 x 0.15
Maximum speed ( v ) = 10.371
Maximum speed ( v ) = 10.4 m/s (Approx)
The speed that the person needs to leave the ground will be 4.32m/s
From the question given,
Height = 95cm
Since the person leave the ground v = 0m/s
acceleration due to gravity g = 9.8m/s²
Using the equation of motion
v² = u² + 2as
a = -g (upward motion)
s = h (distance changes to height)
The equation will become:
0² = u² - 2gh
0² = u² - 2(9.8)(0.95)
u² = 18.62
u = √18.62
u = 4.32
Hence the speed that the person needs to leave the ground will be 4.32m/s
Learn more here: brainly.com/question/20352766
Atoms are a single entity (one type of element) whereas a molecule is a group of 2 or more atoms chemically bonded. Don't be confused that atoms are a single particle because they can be split into protons, neutrons and electrons.
To solve this problem, we will start by defining each of the variables given and proceed to find the modulus of elasticity of the object. We will calculate the deformation per unit of elastic volume and finally we will calculate the net energy of the system. Let's start defining the variables
Yield Strength of the metal specimen
Yield Strain of the Specimen
Diameter of the test-specimen
Gage length of the Specimen
Modulus of elasticity
Strain energy per unit volume at the elastic limit is
Considering that the net strain energy of the sample is
Therefore the net strain energy of the sample is 
