Two point charges, initially 2 cm apart, are moved to a distance of 10 cm apart. By what factor does the resulting electric forc

Question

yaroslaw [1]

3 years ago

6

Two point charges, initially 2 cm apart, are moved to a distance of 10 cm apart. By what factor does the resulting electric forc

e
between them change?
a 25
b.5
C.1/5
D.1/25

Physics

2 answers:

choli [55] · Answer 1 · 2022-05-01T20:10:40+03:00

choli [55]3 years ago

5 0

Answer: The correct answer is C.

2/10 is simplified to 1/5, that is the factor that changes.

xz_007 [3.2K] · Answer 2 · 2022-05-01T22:00:10+03:00

Answer:

1/25

Explanation:

Coulombs law states that the force of attraction between two charges q and Q is directly proportional to the product of the charges and inversely proportional to the square of the distance r between them.

It is expressed as;.

F = kqQ/r²

If two point charges, initially 2 cm apart, the force between them will be;

F = kqQ/2²

F = kqQ/4 ... (1)

If the charges are now moved to a distance of 10cm apart, the force between them will then become;

F2 = kqQ/10²

F2 = kqQ/100.. (2)

Dividing equation 2 by 1;

F2/F = (kqQ/4)/kqQ/10)

F2/F = kqQ/100 × 4/kqQ

F2/F = 1/25

F2 = (1/25)F

The resulting electric force

between the changes by 1/25 since that serves as the constant of proportionality between the two forces