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Archy [21]
3 years ago
14

True or false a microchip lets computers process infomation very quickly

Physics
1 answer:
lisov135 [29]3 years ago
7 0
Yes, that statement is true. 

Microchips are specifically designed to make computers process information much faster, and make the devices a lot more portable. 
You might be interested in
The vertical velocity
cestrela7 [59]

it would be at least 9.8m/s


3 0
3 years ago
On a cold winter day, a penny (mass 2.50 g) and a nickel (mass 5.00 g) are lying on the smooth (frictionless) surface of a froze
sp2606 [1]

Answer:

0.78333 m/s in the opposite direction

1.566 m/s in the same direction

Explanation:

m_1 = Mass of penny = 0.0025 kg

m_2 = Mass of nickel = 0.005 kg

u_1 = Initial Velocity of penny = 2.35 m/s

u_2 = Initial Velocity of nickel = 0 m/s

v_1 = Final Velocity of penny

v_2 = Final Velocity of nickel

As momentum and Energy is conserved

m_{1}u_{1}+m_{2}u_{2}=m_{1}v_{1}+m_{2}v_{2}

{\tfrac {1}{2}}m_{1}u_{1}^{2}+{\tfrac {1}{2}}m_{2}u_{2}^{2}={\tfrac {1}{2}}m_{1}v_{1}^{2}+{\tfrac {1}{2}}m_{2}v_{2}^{2}

From the two equations we get

v_{1}=\frac{m_1-m_2}{m_1+m_2}u_{1}+\frac{2m_2}{m_1+m_2}u_2\\\Rightarrow v_1=\frac{0.0025-0.005}{0.0025+0.005}\times 2.35+\frac{2\times 0.5}{0.4005+0.5}\times 0\\\Rightarrow v_1=-0.78333\ m/s

The final velocity of the penny is 0.78333 m/s in the opposite direction

v_{2}=\frac{2m_1}{m_1+m_2}u_{1}+\frac{m_2-m_1}{m_1+m_2}u_2\\\Rightarrow v_2=\frac{2\times 0.0025}{0.0025+0.005}\times 2.35+\frac{0.005-0.0025}{0.005+0.0025}\times 0\\\Rightarrow v_2=1.566\ m/s

The final velocity of the nickel is 1.566 m/s in the same direction

6 0
3 years ago
If you started counting from 1st grade, how many years of education would the typical professional astronomer have today, at min
allochka39001 [22]

Answer:

16 years

Explanation:

I hope this helps.

4 0
2 years ago
Read 2 more answers
How far would a cantaloupe fall in 5.0 seconds of true free fall?
RUDIKE [14]

Answer:

i think the answer is about 50 m/s

7 0
3 years ago
A charged isolated metal sphere of diameter 15 cm has a potential of 8500 V relative to V = 0 at infinity. Calculate the energy
Elan Coil [88]

Answer:

u = 0.057 J/m^3

Explanation:

Energy density near the surface of the sphere is given by the formula

u = \frac{1}{2}\epsilon_0 E^2

also for sphere surface we know that

E = \frac{V}{R}

R = radius of sphere

V = potential of the surface

now we have

u = \frac{1}{2}\epsilon_0 (\frac{V^2}{R^2})

now from the above formula we have

u = \frac{1}{2}(8.85 \times 10^{-12})(\frac{8500^2}{0.075^2})

u = 0.057 J/m^3

6 0
3 years ago
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