The K.E. of that mass at this height is 40J.
Answer:
10
Explanation:
Each time you want to move up the scale, the number is multiplied by 10. The opposite is true when moving down; you must divide by 10.
Answer:
k = 200 N/m
Explanation:
given,
mass of the object = 251 g
= 251 x 10⁻³ Kg = 0.251 Kg
distance of tendon stretch = x = 1.23 cm
= 1.23 x 10⁻² = 0.0123 m
using the formula
F = k x
where
k is the force constant of the tendon
F = m g
F = 0.251 x 9.8 = 2.4598 N
2.4598 = k x 0.0123
k = 199.98 N/m
k = 200 N/m
hence, force constant of the tendon is approximately equal to 200 N/m
