There are many combinations because it is not all about the number of chemicals, but also about the size of the strand. The longer the strand the more combinations there are and more variations and various lengths provide various results.
Answer:
5.995 psi
Explanation:
30 psi = 2.04 atm
75 mL = 0.075 L
15 mL = 0.015 L
0.075 L/ 2.04 atm = 0.015 L/x
0.075x = 0.0306
x = 0.408
0.408 atm = 5.995 psi
Answer: 3.024 g grams of hydrogen are needed to convert 76 grams of chromium(III) oxide, 
Explanation:
The reaction equation for given reaction is as follows.
Here, 1 mole of reacts with 3 moles of 
.
As mass of chromium (III) oxide is given as 76 g and molar mass of chromium (III) oxide 
is 152 g/mol.
Number of moles is the mass of substance divided by its molar mass. So, moles of is calculated as follows.
Now, moles of .given by 0.5 mol of is calculated as follows.
As molar mass of is 2.016 g/mol. Therefore, mass of is calculated as follows.
Thus, we can conclude that 3.024 g grams of hydrogen are needed to convert 76 grams of chromium(III) oxide, .
Answer:
ICI 204448 hydrochloride | C23H27Cl3N2O4 | CID 129407 - structure, chemical names, physical and chemical properties, classification, patents, literature, etc...
hope this helps!! have an amazing day <3
Answer:
40.8g of sodium sulfate must be added
Explanation:
The reaction of barium nitrate, Ba(NO₃)₂ with sodium sulfate, Na₂SO₄ is:
Ba(NO₃)₂ + Na₂SO₄ → 2 NaNO₃ + BaSO₄(s)
That means, for a complete reaction of an amount of barium nitrate you must add the same amount in moles of sodium sulfate. To solve this problem we need to convert the mass of barium nitrate to moles = Moles of sodium sulfate that must be added:
<em>Moles Ba(NO₃)₂ -Molar mass: 261.3g/mol-:</em>
75g * (1mol / 261.3g) = 0.287 moles = Moles Na₂SO₄
<em>Mass Na₂SO₄ -Molar mass: 142.04g/mol-:</em>
0.287 moles * (142.04g / mol) =
<h3>40.8g of sodium sulfate must be added</h3>
