Answer:
Explanation:
Given,
- mass of the first particle =
- velocity of the first particle =
- mass of the second particle =
- velocity of the second particle =
- Time interval =
Let 
be the initial velocity of the center of mass of the system of particle at time 
Assuming that the first particle is at origin, distance of the second particle from the origin is 'd'
Center of mass of the system of particles
Hence, at time 
, the center of mass of the system is at 
at an initial speed of
Both the particles are assumed to be the point masses, therefore at the time 
the center of mass is at the position of the second particle which should be equal to the total distance traveled by the first particle because the second particle is at rest.
Let 
be the distance traveled by the center of mass of the system of particles in the time interval 
From the kinematics,
Hence, this is the required distance traveled by the first mass to collide with the second mass which is at rest.
THe first one and the third one!!
The component of waves must have same frequency and phase.
when the component of waves vibrate at the same rate and attain maximum point at the same time, reinforcement of the waves amplitude occur to cause a constructive interference.However, when the two waves are out of phase where one is at minimum when the other is at maximum a destructive interference happens.
Answer:
dehydration, lots of sweating, heat stroke, heat exhaustion: nausea, dizziness, vomitting, diahreaa, headache
Explanation:
Answer:
E = 1580594.95 N/C
Explanation:
To find the electric field inside the the non-conducting shell for r=11.2cm you use the Gauss' law:
(1)
dS: differential of the Gaussian surface
Qin: charge inside the Gaussian surface
εo: dielectric permittivity of vacuum = 8.85 × 10-12 C2/N ∙ m2
The electric field is parallel to the dS vector. In this case you have the surface of a sphere, thus you have:
(2)
Qin is calculate by using the charge density:
(3)
Vin is the volume of the spherical shell enclosed by the surface. a is the inner radius.
The charge density is given by:
Next, you use the results of (3), (2) and (1):
Finally, you replace the values of all parameters, and for r = 11.2cm = 0.112m you obtain:
hence, the electric field is 1580594.95 N/C
