Answer:
v = 0.5 [m/s]
Explanation:
In order to determine the speed in such a time interval, we must calculate the slope between the last two positions.
The slope of a line is determined by the following mathematical expression.
P₂ = point 2 = (12,12) = (x₂,y₂)
P₁ = Point 1 = (6,9) = (x₁,y₁)
In this specific case, we must see that in the x-axis we have time, and on the y-axis, we have the space axis.
Now using the slope:

This slope is equal to the speed (velocity)
v = 0.5 [m/s]
Explanation:
It is given that,
Radius of curvature of the mirror, R = 1.54 cm
(a) We have to find the focal length of the mirror. The relationship between the focal length and the radius of curvature is given by :

f = focal length of the mirror

f = 0.77 cm
(b) The power of mirror is given by the reciprocal of focal length i.e.
Power, 
P = 1.29 diopters
Hence, this is the required solution.
We can answer this problem using Ampere’s Law:
<span>Bh = μoNI </span>
Where:
B = Magnetic Field
h = coil length
<span>μo = permeability =4π*10^-7 T·m/A </span>
N = number of turns
I = current
It is given that B=0.0015T, I=1.0A, h=10 cm =
0.1m<span>
Use Ampere's law to find # turns:
Which can be rewritten as:
<span>N = Bh/μoI </span>
N = (0.0015)(0.1)/(4π*10^-7)(1.0)
N = 119.4
</span>
<span>Answer:
119.4 turns</span>
Point X lies on a horizontal line. We can intuitively say that the slope of the graph at point X is 0, therefore the acceleration at point X is 0m/s²
Point Y lies on a downward slanting line. To calculate the slope of that line, let's apply this equation:
m = (y₂-y₁)/(x₂-x₁)
m = slope, (x₁, y₁) and (x₂, y₂) correspond to the coordinates of the line's endpoints.
Given values:
(x₁, y₁) = (7, 5)
(x₂, y₂) = (12, 0)
Plug in and solve for m:
m = (0 - 5)/(12 - 7)
m = -1
The acceleration at point Y is -1m/s²
Choice A
Answer:

Explanation:
As we know that truck is moving up the hill
So here we have two forces on the crate placed on the truck
1) gravitational force along the floor
2) Friction force along the floor
Now here if the truck is moving with maximum possible acceleration so that there is no slipping of the crate
So here we will have



