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Natasha2012 [34]
3 years ago
10

[ Simple machine ]

Physics
1 answer:
AleksAgata [21]3 years ago
6 0

Answer:

Answer:

2.5 m

Explanation:

Load ( L ) = 500 N

Effort ( E ) = 200 N

Load distance ( LD ) = 3 m

Effort distance ( ED ) = ?

Now, Let's find the Effort distance ( ED )

We know that,

Output work = Input work

i.e L × LD = E × ED

plug the values

multiply the numbers

Swipe the sides of the equation

Divide both sides of the equation by 200

Calculate

Hope this helps..

best regards!!

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An astronaut has a mass of 75 kg and is floating in space 500 m from his 125,000 kg spacecraft. What will be the force of gravit
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Answer:

1. 2.5×10¯⁹ N

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Explanation:

1. Determination of the force of attraction.

Mass of astronaut (M₁) = 75 Kg

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F = 2.5×10¯⁹ N

Thus, the force of attraction between the astronaut and his spacecraft is 2.5×10¯⁹ N

2. Determination of the acceleration of the astronaut.

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Acceleration (a) of astronaut =?

The acceleration of the astronaut can be obtained as follow:

F = ma

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<em>NOTE: The question b) will be changed in other to give a meaningful answer, because it is the same speed as the original (the gallons would be 1.9, as in the original).</em>

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