Answer:
humans? i believe it would be because we're mammals.
Answer:
none
Explanation:
it's to high up to be affected by the gravity
Answer:
Part a)
![A = 1.78 m](https://tex.z-dn.net/?f=A%20%3D%201.78%20m)
Part b)
![f = 2 rev/s](https://tex.z-dn.net/?f=f%20%3D%202%20rev%2Fs)
Explanation:
Part A)
As we know that time period of the motion is given as
![T = 2.68 s](https://tex.z-dn.net/?f=T%20%3D%202.68%20s)
so we have
![\omega = \frac{2\pi}{T}](https://tex.z-dn.net/?f=%5Comega%20%3D%20%5Cfrac%7B2%5Cpi%7D%7BT%7D)
![\omega = \frac{2\pi}{2.68}](https://tex.z-dn.net/?f=%5Comega%20%3D%20%5Cfrac%7B2%5Cpi%7D%7B2.68%7D)
![\omega = 2.34 rad/s](https://tex.z-dn.net/?f=%5Comega%20%3D%202.34%20rad%2Fs)
now at the point of maximum amplitude the force equation when Normal force is about to zero is given as
![mg = m\omega^2 A](https://tex.z-dn.net/?f=mg%20%3D%20m%5Comega%5E2%20A)
so we have
![A = \frac{g}{\omega^2}](https://tex.z-dn.net/?f=A%20%3D%20%5Cfrac%7Bg%7D%7B%5Comega%5E2%7D)
![A = \frac{9.81}{2.34^2}](https://tex.z-dn.net/?f=A%20%3D%20%5Cfrac%7B9.81%7D%7B2.34%5E2%7D)
![A = 1.78 m](https://tex.z-dn.net/?f=A%20%3D%201.78%20m)
Part b)
Now if the amplitude of the SHM is 6.23 cm
and now at this amplitude if object will lose the contact then in that case again we have
![mg = m\omega^2 A](https://tex.z-dn.net/?f=mg%20%3D%20m%5Comega%5E2%20A)
![g = \omega^2 (0.0623)](https://tex.z-dn.net/?f=g%20%3D%20%5Comega%5E2%20%280.0623%29)
![\omega = 12.5 rad/s](https://tex.z-dn.net/?f=%5Comega%20%3D%2012.5%20rad%2Fs)
so now we have
![2\pi f = 12.5](https://tex.z-dn.net/?f=2%5Cpi%20f%20%3D%2012.5)
![f = 2 rev/s](https://tex.z-dn.net/?f=f%20%3D%202%20rev%2Fs)
Refraction is
the bending of the waves which is result of the fact that different parts of
the wave reach the water with different speeds because of the angle approaching
the shore.
<span>The
wave refraction disperses the wave energy in quiet water areas and sand is
deposited.<span> </span></span>
Answer:
ΔX = λ = 0.68 m
Explanation:
Wave speed is related to wavelength and frequency by the equation
v = λ f
where the speed of sound is 340 m / s
λ = v / f
λ = 340/500
λ = 0.68 m
this is the wavelength, it is the minimum distance for which the wave epitates its movement, which is equal to the distance between two consecutive compressions of the sound
ΔX = λ = 0.68 m