<span>The loudness of the sound increases gradually as the air is slowly introduced in to the jar. This is because sound needs a physical medium and in a vacuum there is none. The air provides that medium and as it is introduced, the transfer of sound energy increases</span>
Through Shannon's Theorem, we can calculate the capacity of the communications channel using the value of its bandwidth and signal-to-noise ratio. The capacity, C, can be expressed as
C = B × log₂(1 + S/N)
where B is the bandwidth of the channel and S/N is its signal-to-noise ratio.
Since the given SN ratio is in decibels, we must first express it as a ratio with no units as
SN (in decibels) = 10 × log (S/N)
30 = 10log(S/N)
log(S/N) = 3
S/N = 10³ = 1000
Now that we have S/N, we can solve for its capacity (in bits per second) as
C = 4000 × log₂(1 + 1000)
C = 39868.91 bps
Thus, the maximum capacity of the channel is 39868 bps or 40 kbps.
Answer: 40 kbps
Answer:
Explanation:
The acceleration of an object (or a person, as in this case) is given by
where
v is the final velocity
u is the initial velocity
t is the time interval
In this problem,
u = 20 m/s
v = 40 m/s
t = 10 s
Therefore Jill's acceleration is
The initial velocity of the sled will be 7.34 m/sec. V is the initial velocity of the sled.
<h3>What is the law of conservation of momentum?</h3>
According to the law of conservation of momentum, the momentum of the body before the collision is always equal to the momentum of the body after the collision.
The given data in the problem is;
(m₁) mass of child = 38 kg
(u₁) is the initial velocity child = 2.2 m/s
(m₂) is the mass of sled = 68 kg
(u₂) is the initial velocity of sled = ?
(v) is the velocity after collision = 5.5 m/s
According to the law of conservation of momentum;
Momentum before collision =Momentum after collision
Hence,the initial velocity of the sled will be 7.34 m/sec.
To learn more about the law of conservation of momentum refer;
brainly.com/question/1113396
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Answer:
The magnitud of the torque doing by the foot at the point where the shaft is attached is 0.063 Nm
Explanation:
The torque is obtained by multiplying the longitude from the shaft attached point to force acting point by the force perpendicular component:
T = d * Fp
Notice that the perpindicular component is the total force magnitud times the sino of the angle respect the horizontal:
Fp = F*sin(a)
Replacing the values for the force and the angle:
Fp = 33N*sin(π/5) = 33N * 0.011 = 0.363 N
Taking the distance in meters:
T = 0.2m * 0.363 N = 0.063 Nm
