Answer:
0.011 N-m
Explanation:
Given that
The mass of a solid cylinder, m = 30 kg
The radius of the cylinder, r = 0.18 m
The acceleration of the cylinder,
It rotates about an axis through its center. We need to find the torque acting on the cylinder. The formula for the torque is given by :
Where
I is the moment of inertia of the cylinder,
For cylinder,
So,
So, the required torque on the cylinder is 0.011 N-m.
Write an equation to calculate the force between two objects if the product of their charges is 10.0 × 10-4 C. (Note: Use the variable R for the distance between the charges.)
F = 900 ÷_________
<span>In order to answer this question you need to know the specific heat of aluminum and water.
The source below says 0.900 J/g K and 4.186 J/g K respectively.
Let T be the final temperature to be found:
(0.900 J/g K) x (270 g) x (T - (-20))K = (243T + 4860) J gained by the Al
(4.186 J/g K) x (500 g) x (85 - T)K = (177905 - 2093T ) J lost by the coffee
Set the two expressions for heat gained/lost equal to each other:
243T + 4860 = 177905 - 2093T
Solve for T algebraically:
T = 74.1 °C</span>
Answer:
The coil radius of other generator is 5.15 cm
Explanation:
Consider the equation for induced emf in a generator coil:
EMF = NBAω Sin(ωt)
where,
N = No. of turns in coil
B = magnetic field
A = Cross-sectional area of coil = π r²
ω = angular velocity
t = time
It is given that for both the coils magnetic field, no. of turn and frequency is same. Since, the frequency is same, therefore, the angular velocity, will also be same. As, ω = 2πft.
Therefore, EMF for both coils or generators will be:
EMF₁ = NBπr₁²ω Sin(ωt)
EMF₂ = NBπr₂²ω Sin(ωt)
dividing both the equations:
EMF₁/EMF₂ = (r₁/r₂)²
r₂ = r₁ √(EMF₂/EMF₁)
where,
EMF₁ = 1.8 V
EMF₂ = 3.9 V
r₁ = 3.5 cm
r₂ = ?
Therefore,
r₂ = (3.5 cm)√(3.9 V/1.8 V)
<u>r₂ = 5.15 cm</u>
For any circuit element, the power is equal to the voltage difference across the element multiplied by the current. By Ohm's Law, V = IR, and so there are additional forms of the electric power formula for resistors. Power is measured in units of Watts (W), where a Watt is equal to a Joule per second (1 W = 1 J/s).