When the system reaches 60° North latitude after moving away from the equator and passing directly over water, it will be at a point where most of its energy is lost.
The low pressure system will dissipate its energy as it propagates through the air and more energy will be lost due to the high content of water vapor in the air above the water.
The answer is option C .Because as the direction of the boy changes ;velocity changes .
Answer:
v₀ = 50.46 m / s
Explanation:
This is a projectile launch exercise where the scope is given by
R = v₀² sin 2 θ / g
Let's clear the initial speed
v₀ = √(G R / sin 2θ
)
Let's reduce the distance
R = 0.3 km (1000m / 1km)
R = 300 m
Let's calculate
v₀ = √ (9.8 300 / sin2 π / 6)
Let's calculate the breast in radians
sin π / 3 = 0.8660
v₀ = √ (2546.11)
v₀ = 50.46 m / s