Question

Dos coches, uno de 1.000 kg que circula a 100 km/h, y otro de 1.200 kg que circula a 90

Answer 1

The collision of car 2 is more violent (because more impulse is exerted)

Explanation:

The collision which is more violent is the one in which more impulse is exchanged.

The impulse exerted by each car on the wall is equal to the change in momentum of the car:

$I=m\Delta v$

where

m is the mass of the car

$\Delta v$ is the change in velocity

For the car 1,

m = 1000 kg

$\Delta v = -100 km/h \cdot \frac{1000 m/km}{3600 s/h}=-27.8 m/s$ (the sign is negative because the velocity of the car has changed from 100 km/h to 0 km/h)

So the magnitude of the impulse of car 1 is

$I_1 = (1000)(27.8)=27,800 kg m/s$

For the car 2,

m = 1200 kg

$\Delta v = -90 km/h \cdot \frac{1000 m/km}{3600 s/h}=-25 m/s$

So the magnitude of the impulse of car 2 is

$I_2 = (1200)(25)=30,000 kg m/s$

So, car 2 exerts a larger impulse, therefore its impact is more violent.

Learn more about impulse and change in momentum:

brainly.com/question/9484203

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