1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Allushta [10]
3 years ago
6

You have a sample that has a h3o+ concentration of 1.25 x 10-5 m. what would be the [oh-]?

Chemistry
1 answer:
deff fn [24]3 years ago
7 0

Answer:

[OH⁻] = 8x10⁻¹⁰

Explanation:

Kw = 1x10⁻¹⁴

Kw = [H₃O⁺] . [OH⁻]

1x10⁻¹⁴ = 1.25x10⁻⁵ . [OH⁻]

1x10⁻¹⁴ / 1.25x10⁻⁵ = [OH⁻]

[OH⁻] = 8x10⁻¹⁰

You might be interested in
Example of a neutral mutation?
Norma-Jean [14]

The answer is D

Explanation: A RED FLOWER WITH ONE PART COLORED YELLOW

3 0
3 years ago
Read 2 more answers
Use the activity series below to predict the products of each of the following reactions. Do not worry about
myrzilka [38]

Answer:

i) CCl₄ and Br₂ does not react

ii) CBr₄ + Cl₂ → CCl₄ + Br₂

Explanation:

i) CCl₄ + Br₂ (no reaction)

From the given activity series, we have that chlorine gas, Cl₂, is more reactive than bromine gas, Br₂, therefore, a reaction of CCl₄ + Br₂ will not have a reaction as the propensity for the chlorine to stay combined with the carbon is higher than the ability for bromine to remain combined with or attract the carbon. Therefore, for CCl₄ + Br₂ there is no reaction

ii) CBr₄ + Cl₂

From the given activity series, we have that chlorine gas, Cl₂, is more reactive than bromine gas, Br₂, therefore, a reaction of CBr₄ + Cl₂ will give products that will have the Br in the CBr₄ replaced by the Cl₂ as follows;

CBr₄ + Cl₂ → CCl₄ + Br₂

The products of the reaction of CBr₄ and Cl₂ are therefore CBr₄ and Cl₂.

8 0
2 years ago
Linoleic acid is a polyunsaturated fatty acid found, in ester form, in many fats and oils. Its doubly allylic hydrogens are part
Ganezh [65]

Answer:

Explanation:

Linoleic acid, which is polyunsaturated fatty acid, found

the three resonance structures are given as,

8 0
3 years ago
If the volume and moles of a container are held constant, the temperature of a gas is inversely proportional to the pressure.
noname [10]

Answer:

FALSE

Explanation:

Assuming that the gas is ideal

Therefore the gas obeys the ideal gas equation

<h3>Ideal gas equation is </h3><h3>P × V = n × R × T</h3>

where

P is the pressure exerted by the gas

V is the volume occupied by the gas

n is the number of moles of the gas

R is the ideal gas constant

T is the temperature of the gas

Here volume of the gas will be the volume of the container

Given the volume of the container and number of moles of the gas are constant

As R will also be constant, the pressure of the gas will be directly proportional to the temperature of the gas

P ∝ T

∴ Pressure will be directly proportional to the temperature

4 0
3 years ago
Can yall help me in this pleaseee, i dont get how im supposed to do it..​
blagie [28]
It is a triangular shape and there 26 electrons all together but when shared each individual element has 8
3 0
3 years ago
Other questions:
  • Which item is made from an alloy? A. steel tray B. glass plate C. credit card D. copper wire
    10·2 answers
  • How many electrons does an atom have
    9·1 answer
  • Brainliest will be given! Please help!
    6·1 answer
  • Surface tension ________________________.
    15·1 answer
  • An element is lustrous, brittle, and silver colored. What type of element is it
    9·1 answer
  • Describe what the isotopes of an element have in common and how are they different.
    10·2 answers
  • 28. The formula for magnesium nitride is____.<br> a. MgN<br> b. MgN3<br> c. Mg3N2<br> d. Mg2N3
    14·2 answers
  • Which of the following is not a result when a change to an equilibrium system is applied? Increasing the rate of the forward rea
    8·2 answers
  • Which represents an endothermic reaction
    12·2 answers
  • What is the molarity of 0.25 moles of KBr dissolved into 250 ml of solution?
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!