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tigry1 [53]
2 years ago
5

Use the activity series below to predict the products of each of the following reactions. Do not worry about

Chemistry
1 answer:
myrzilka [38]2 years ago
8 0

Answer:

i) CCl₄ and Br₂ does not react

ii) CBr₄ + Cl₂ → CCl₄ + Br₂

Explanation:

i) CCl₄ + Br₂ (no reaction)

From the given activity series, we have that chlorine gas, Cl₂, is more reactive than bromine gas, Br₂, therefore, a reaction of CCl₄ + Br₂ will not have a reaction as the propensity for the chlorine to stay combined with the carbon is higher than the ability for bromine to remain combined with or attract the carbon. Therefore, for CCl₄ + Br₂ there is no reaction

ii) CBr₄ + Cl₂

From the given activity series, we have that chlorine gas, Cl₂, is more reactive than bromine gas, Br₂, therefore, a reaction of CBr₄ + Cl₂ will give products that will have the Br in the CBr₄ replaced by the Cl₂ as follows;

CBr₄ + Cl₂ → CCl₄ + Br₂

The products of the reaction of CBr₄ and Cl₂ are therefore CBr₄ and Cl₂.

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The following reaction shows sodium carbonate reacting with calcium hydroxide.
velikii [3]

Ans: 15.1 grams

Given reaction:

Na2CO3 + Ca(OH)2 → 2NaOH + CaCO3

Mass of Na2CO3 = 20.0 g

Molar mass of Na2CO3 = 105.985 g/mol

# moles of Na2CO3 = 20/105.985 = 0.1887 moles

Based on the reaction stoichiometry: 1 mole of Na2CO3 produces 2 moles of NaOH

# moles of NaOH produced = 0.1887*2 = 0.3774 moles

Molar mass of NaOH = 22.989 + 15.999 + 1.008 = 39.996 g/mol

Mass of NaOH produced = 0.3774*39.996 = 15.09 grams


5 0
2 years ago
What is △n for the following equation in relating Kc to Kp?
Nimfa-mama [501]

Answer:

-1  

Explanation:

The relation between Kp and Kc is given below:

K_p= K_c\times (RT)^{\Delta n}

Where,  

Kp is the pressure equilibrium constant

Kc is the molar equilibrium constant

R is gas constant , 0.082057 L atm.mol⁻¹K⁻¹

T is the temperature in Kelvins

Δn = (No. of moles of gaseous products)-(No. of moles of gaseous reactants)

For the first equilibrium reaction:

2Na_{(s)}+2H_2O_{(l)}\rightleftharpoons 2NaOH_{(aq)}+2H_2_{(g)}

<u>Δn = (No. of moles of gaseous products)-(No. of moles of gaseous reactants)  = (2+1)-(2+2) = -1  </u>

<u></u>

7 0
3 years ago
How is the pH of an acidic substance raised?
BabaBlast [244]

Answer: 4) Concentrate it

Explanation:

4 0
2 years ago
If 23.17 g of beryllium (Be) reacts with water at standard temperature and pressure,
emmainna [20.7K]

Volume of H2 produced = 57.6576 L

<h3>Further explanation</h3>

Given

23.17 g Be

Required

Volume of H2

Solution

Reaction

Be(s)+H2O(g)→BeO(s)+H2(g)

mol Be :

= 23.17 g : 9 g/mol

= 2.574

From the equation, mol H2 : mol Be = 1 : 1, so mol H2 = 2.574

Volume H2(assumed at STP, 1 mol=22.4 L) :

= 2.574 x 22.4 L

= 57.6576 L

5 0
2 years ago
Use the relative humidity table and the data to answer the question.
Dahasolnce [82]

Answer:

Explanation:

B

5 0
2 years ago
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