If light travels from oil (slower medium) to water (faster medium) at an angle, what happens to the direction of the light ray i
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Answer:
(a) Magnitude of seat force at lowest point = 678 + 92 = 770
(b) Force exerted by the seat (highest point) = 310 N
(c) Force exerted by seat (lowest point) = 1046 N
Explanation:
At the highest point the magnitude of force by the seat = 586 N
The weight of the student = 678 N
Thus, at the highest point, the difference in this force is due to the centrifugal force acting on the boy. This can be calculated as follows:
Centrifugal Force = 678 - 586 = 92 N
(a) The magnitude of force on the student by the seat at the lowest point will have to appose both the student's weight and centrifugal force acting towards the ground. This would mean:
Magnitude of seat force at lowest point = 678 + 92 = 770 N
(b) If the wheel's speed is doubled, the centrifugal force will change accordingly. The equation of centrifugal force is given below:
We can see from this that the force is directly proportional to the square of the velocity. So if the velocity is doubled, the centrifugal force increases four times.
So at the highest point the centrifugal force will decrease the force of weight acting on the seat. The seat force would then be:
Force exerted by the seat = Weight - Centrifugal force
Force exerted by the seat = 678 - (4 * 92)
Force exerted by the seat (highest point) = 310 N
(c) The force exerted by the seat at the lowest point will be the centrifugal force plus the weight.
This is:
Force exerted by seat = Centrifugal force + Weight
Force exerted by seat = (4 * 92) + 678
Force exerted by seat (lowest point) = 1046 N
Answer:
The electric field strength needed is 4 x 10⁵ N/C
Explanation:
Given;
magnitude of magnetic field, B = 0.1 T
velocity of the charge, v = 4 x 10⁶ m/s
The velocity of the charge when there is a balance in the magnetic and electric force is given by;
where;
v is the velocity of the charge
E is the electric field strength
B is the magnetic field strength
The electric field strength needed is calculated as;
E = vB
E = 4 x 10⁶ x 0.1
E = 4 x 10⁵ N/C
Therefore, the electric field strength needed is 4 x 10⁵ N/C