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3 years ago

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If light travels from oil (slower medium) to water (faster medium) at an angle, what happens to the direction of the light ray i

n water with respect to normal?
A. It moves away from the normal. B. It moves toward the normal.
C. It will move along the normal. D. It will move perpendicular to the normal.
E. It stops traveling.

1 answer:

iVinArrow [24]3 years ago

7 0

If light travels from oil to water at an angle, what happens to the direction of the light ray in water with respect to the normal, is it moves away from the normal.

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Suppose you are driving a car and your friend, who is with you in the car, tosses a softball up and down from her point of view.

Sholpan [36]

Answer:

No, i disagree.

Explanation:

If the car is moving, it only has a velocity with a component in the horizontal direction. If we use galilean relativity, the velocity of the ball observed by my friend standing in the ground should only be affected in the horizonal direction, while the vertical stays the same for both observers.

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2 years ago

Why is the direction of position V upwards?

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Answer:

The wave is moving from left to right (as indicated by the arrow), so, given that at the current instance the amplitude of the position V is 0 (or whatever midpoint the dashed line corresponds to), in the immediately next instance the position will continue increasing as the wave moves from left to right. The peak currently shown at U will at some point "arrive" at V. At that point the location V will have the maximum amplitude. After that the direction at position will be downward, etc.

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2 years ago

Assume that a clay model of a lion has a mass of 0.225 kg and travels on the ice at a speed of 0.85 m/s. It hits another clay mo

Charra [1.4K]

Answer:

Final velocity will be equal to 0.321 m/sec

Explanation:

We have given mass of clay model of lion $m_1=0.225kg$

Its speed is 0.85 m/sec, so $v_1=0.85m/sec$

Mass of another clay model $m_2=0.37kg$

It is given that second clay is motionless

So its velocity $v_2=0m/sec$

Now according to conservation of momentum

Momentum before collision will be equal to momentum after collision

So $m_1v_!+m_2v_2=(m_1+m_2)v$ , here v is velocity after collision

So $0.225\times 0.85+0.37\times 0+(0.225+0.37)v$

$0.595v=0.191$

v = 0.321 m/sec

So final velocity will be equal to 0.321 m/sec

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2 years ago

The driver of a car traveling at 23.1 m/s applies the brakes and undergoes a constant

Vsevolod [243]

Answer:

The tires make 125 revolutions before the car stops

Explanation:

Circular and Linear Motion

A tire rotates around a fixed point and the tire when in contact with the ground, drives a vehicle in a linear path. This is an example of a relationship between both types of movements that can be taking place simultaneously.

The car is moving with an initial speed of $v_o=23.1\ m/s$ and then breaks at $a=-1.03\ m/s^2$ until it stops. We can compute the time take to stop by using

$\displaystyle v_f=v_o+a.t$

Solving for t

$\displaystyle t=\frac{v_f-v_o}{a}$

Putting in numbers

$\displaystyle t=\frac{0-23.1}{-1.03}$

$\displaystyle t=22.427\ sec$

Now, let's transfer this information to the circular motion. We know the tangent speed is

$\displaystyle v_t=w.r$

Being w the angular speed and r the radius of the circle, in this case, the tires. The tangent speed is the same as the speed of motion of the car. It gives us the initial angular speed

$\displaystyle w_o=\frac{v_t}{r}$

$\displaystyle w_o=\frac{23.1}{0.33}=70\ rad/s$

When the circular motion is not uniform, i.e. there is angular acceleration $\alpha$ , the angular speed is a function of time

$\displaystyle w=w_o+\alpha t$

We can compute the angular acceleration knowing the final angular speed is zero when the car stops.

$\displaystyle \alpha=\frac{w-w_o}{t}=\frac{0-70}{22.427}$

$\displaystyle \alpha=-3.121\ rad/s^2$

The rotation angle is also a function of time as shown

$\displaystyle \theta=w_o\ t+\frac{\alpha t^2}{2}$

Using the given and computed values

$\displaystyle =70(22.427)-\frac{3.121(22.427)^2}{2}$

$\displaystyle \theta =784.95\ rad$

Knowing each revolution is $2\pi$ radians, the number of revolutions is

$\displaystyle n=\frac{\theta }{2\pi}=125\ rev$

The tires make 125 revolutions before the car stops

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3 years ago

Many physical quantities are connected by inverse square laws, that is, by power functions of the form f(x)=kx^(-2). In particul

goldenfox [79]

Answer:

4 times

Explanation:

Since the equation for the illumination of an object, i.e. the brightness of the light, is <em>inversely proportional to the square of the distance from the light source</em>, the form of the function is:

f(x) = k.x⁻²

Where x is the distance between the object and the light force, k is the constant of proportionality, and f(x) is the brightness.

Then, if you move halfway to the lamp the new distance is x/2 and the new brightness (call if F) is :

$F=k(x/2)^{-2}=\frac{k}{(x/2)^2}= \frac{k}{x^2}. 4=f(x).4$

Then, you have found that the light is 4 times as bright as it originally was.

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2 years ago